Damped Oscillatory motion : Period

1 reply · 2K views · last reply
Bedeirnur
Messages
18
Reaction score
0

Relevant equations

1)
Equation ω = square root of (k/m minus b squared over 4m squared), the angular frequency of a damped oscillator.

2) [tex]T = \sqrt{ \frac{m}{k} }[/tex]
3) [tex]T = \frac{2 \pi }{ \omega }[/tex]In some problems about damped oscillatory motion, the requests ask for example "Calculate the amplitude after 20 oscillations"

I know that i need to find the period first of all but :

Do i find the period by using equation number 2? Is that constant? I've seen other threads where they calculated T with (2) and used it for everything but, if we have a different value of \omega overtime, why did we use the initial \omega to find the period?

If i divide 2π by

what do I find? Isn't that the period?
 
Attachments
  • Equation for angular frequency of a damped oscillator: omega equals the square root of the quantity k over m minus b squared over 4m squared.
    upload_2015-4-1_0-15-26.png
    1.2 KB · Views: 549
  • Formula for damped angular frequency: omega equals the square root of the quantity k/m minus b squared over 4m squared.
    upload_2015-4-1_0-15-41.png
    1.3 KB · Views: 568
  • Equation for damped angular frequency: omega equals the square root of k over m minus b squared over 4m squared.
    upload_2015-4-1_0-16-32.png
    1.3 KB · Views: 559
Last edited: