Recent content by big daddy

i'm still lost!

mass is 25 weight is 245..

isn't 0..

the formula is f= ma 277=(245)a a= 277/245 a=1.1 N i think it's not right i'm lost!

i read the whole chapter and i still don't get it i know the compnents of vector first step i think to get normal force:: 80(cos53) and you get 48 N and I'm stuck! i know that i have to find the coffecient of the friction so i can get Ff that's not a homework, I'm studying for a test...

farmhand attaches a 25 Kg bale of hay to one end of a rope passing over a frictionals pulley connected to a beam in the hay barn.then another farmhand pulls down on the opposite end of the rope with force of 277N. ignoring the mass of the rope, find the magntuide and dirction, gravitational...

seld pulled at a constant velocity acroos a horizontal snow surface, if force 80 apploed to the sled rope at an angle of 53 to the ground, what is the magnitude of force of friction of the snow? i don't know how to solve it i have test 2morrow i need some explanition plez