What is the magnitude of force of friction of the snow

AI Thread Summary
To determine the magnitude of the force of friction acting on a sled being pulled at a constant velocity across a horizontal snow surface, the net force is zero. The applied force of 80 N at an angle of 53 degrees can be broken down into its horizontal and vertical components, but the normal force is not necessary for this calculation. The force of friction must equal the horizontal component of the applied force since the sled moves at constant velocity. Understanding the relationship between applied force, friction, and net force is crucial for solving this problem effectively.
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seld pulled at a constant velocity acroos a horizontal snow surface, if force 80 apploed to the sled rope at an angle of 53 to the ground,
what is the magnitude of force of friction of the snow?
i don't know how to solve it
i have test 2morrow
i need some explanition plez
 
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First, please stop writing in "texting" shorthand. It's not Youtube here.

And get used to the other rules: we are not here to answer your homework questions for you. You must show some of your effort before we help you. Do you have a textbook? Read a bit about components of vectors, and coefficient of friction, and normal force.
 
i read the whole chapter and i still don't get it
i know the compnents of vector
first step i think
to get normal force::
80(cos53)
and you get
48 N
and I'm stuck!
i know that i have to find the coffecient of the friction
so i can get Ff
that's not a homework, I'm studying for a test
thanks
 
This is not on a slope. You don't need the normal force here, actually. You need to know a few other things.

What's the net force on this object if it is pulled at a constant velocity?
 
isn't 0..
 
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