so i am going to use the formula
I = R^2 * M
and do
I = 4.1^2*55 + 4.1^2*106?
i got my answer as 5371.41
is that correct?
i get one chance to get it right so just making sure
Question:
A woman with a mass of 55.0 is standing on the rim of a large disk that is rotating at an angular velocity of 0.550 about an axis through its center. The disk has a mass of 106 and a radius of 4.10 .
a.)Calculate the magnitude of the total angular momentum of the...
Q1.) A hollow, spherical shell with mass 1.70 rolls without slipping down a slope angled at 38.0.
-Find the acceleration.
-Find the friction force.
-Find the minimum coefficient of friction needed to prevent slipping.
If it rolls wthout slippng, the increase in Kinetic Energy equals...
I have been working on this problem for 30 min and can;t seem to get anywhere.
Question
You have a amphibian vehicle which can travel 20 mph on the water and 52 mph on the land. You must find the quickest point from point A to C.
-A is 20 Miles east of point B and is all land.
-C is...
ok wow i keep finding how to do stuff.
Ok to get part C. I realized that i had solved for Vf.
So therefore you can use this to find Vi
M1V1+M2V1= (M1+M2)V2
then you can use
K = 1/2 * m1 * V1^2
= 48.4J
ok i forgot the ^2 in theW = 1/2 K (X2-X1)^2
so i did get the right answer but how do i go about getting part C first part.
The second part is clearly zero because it doesn;t have any velocity so there for no kinetic energy.
Ok to solve B i did.
W = 1/2 K (X2-X1) = .5 (159.00)(.45)=35.775
w = (change in K) = .5 (ma + Mb)V2^2
V2 = (35.775/ (1/2 * .45))^(1/2)
however i got 12.6 m/s^2
what was i suppose to do instead?