Oh dang it, I put N=mg. Well I think I got it now. TCosθ-.35N>0, so T(Cosθ+.35Sinθ)>4.459. We want Cosθ+.35Sinθ to be max so T will be min. -Sinθ+.35Cosθ=0, θ=19.29. Then T>4.2. Right?
Ok say there is a force T acting on the toaster at θ above the horizontal. The y component is TSinθ and the x component is TCosθ. We want TCosθ>fstatic so it will move. TCosθ>N(mu) TCosθ>12.74(.350), TCosθ>4.459. Now Cosθ ranges from 1 to 0. The higher Cosθ is, the lower T will be. The highest...
Homework Statement
A 1.3kg toaster is not plugged in. The coefficient of static friction between the toaster and a horizontal countertop is 0.350. To make the toaster start moving, you carelessly pull on its electric cord. (a) For the cord tension to be as small as possible, you should pull...
Homework Statement
Three blocks are connected on a table as shown in Figure P5.50. The table is rough and has a coefficient of kinetic friction of 0.350. The pulleys are frictionless.
Determine the magnitude of acceleration of each block.
Determine the tension in the two cords...
Well the thing I don't understand it how can you make the assumption that segment 2 decreases by x2 and segment 1 increases by x1. So if m2 moves 2m, then segment 1m? How did you get this? I am sorry I don't understand.
You weren't stating the obvious, it was just what I needed to know. Ok so when m2 moves, it causes P1 to move. The net force acting on m2 is m2g-T2(Where T2 is the tension in that string). So m2g-T2=m2a2. T2=m2(g-a2). Let's say the tension in the string of P1 is T1. Because it is accelerating...
Homework Statement
An object of mass m1 on a frictionless horizontal table is
connected to an object of mass m2 through a very light pulley
P1 and a light fixed pulley P2 as shown in Figure P5.34.
(a) If a1 and a2 are the accelerations of m1 and m2, respectively,
what is the relation...
Homework Statement
Two masses m1 and m2 situated on a frictionless, horizontal surface are connected by a light string. A force F is exerted on one of the masses to the right. Determine the acceleration of the system and the tension T in the string.
Homework Equations
F=ma
The...
If he is accelerating downwards then there has to be a net force going down also. I changed to Newtons so 642.25-542.9=ma. m=65.53. You can solve for a. It is easier to visualize him being on a string. That is another way to measure weight. So that makes mg-T=ma. T is the weight shown then.
Homework Statement
You are a judge in a children's kite-flying contest, and two children will win prizes for the kites that pull most strongly and least strongly on their strings. To measure string tensions, you borrow a weight hanger, some slotted weights, and a protractor from your physics...