Recent content by blackdranzer

as long as the volume of the box after mixing remains the same and for an ideal gas, the change in entropy is zero. But, if the volume of the third box is larger then ofcourse, entropy increases... note: Referred from "Entropy and the second law, interpretations and mis-interpretations " Ariah...

Consider three identical boxes of volume V. the first two boxes will contain particles of two different species 'N' and 'n'. The first box contains 'N' identical non interacting particles in a volume V. The second box contains 'n' non interacting particles. The third box is the result of mixing...

i don't understand how it exactly cancels out.. case 1: during the expansion of the gas, dq amount of heat goes into the system and dw amount of work is done by the system. now if the cycle is isothermal, then from the view point of the surroundings, we have : dw <= - dq (the inequality is...

consider an irreversible cycle. There will be no changes in the state variables (like U, S) of the system undergoing the cycle, but for the surroundings, there will be change in the state variables, in fact, entropy increases. my question is, what happens to the internal energy of the...

All definitions of entropy are interconnected...the definition that you posted is a direct result of the 2nd law of thermodynamics which essentially states that heat energy(low grade) cannot be converted to any other form of energy (say mech. work) with 100% efficiency .i.e. there will always be...

From the Bohr/De Broglie postulate we have n λ = 2πr where λ is the De-Broglie wavelength , r is the radius corresponding to n and n is the quantum number. An electron in the state n=2 has more energy than that at n=1 That implies that the De- Broglie wavelength associated with the electron...