Recent content by BlackHayze

So I'm working through a physics a textbook on my own, and because of that don't always have a professor who can help explain concepts I don't understand, so I'm turning to you good folks. Could someone explain why both masses need to be taken into account when determining the acceleration of...

Hi all, I graduated with a degree in math about a year and a half ago. I've recently become very interested in the idea of Physics. I've always loved physics, but for some reason, probably because I never really did the kind of self-introspection I try to practice now, I majored in Math and...

Alright, I get what you're saying now, we were saying the same equation, you were just using a different version of it. I understand how to solve the problem now. Thanks!

But this is an object on a spring, so I don't get where the angular velocity comes in? It's not moving in a circle or rotating, it's oscillating up and down.

I don't recognize the equation you're using. I don't see how angular velocity would come into play here (assuming that the w is omega.) I stuck with x=A*sin(2*pi*f*t + phi) + equilibrium position (we were never given the equation you used for SHM,) 2*pi*f*t was zero since time was zero, so...

UPDATE: I used the bottom position to find phi doing: 1.05 = .39m*sin(0+phi)+1.44 (2*pi*f*t = 0 because t=0 at the lowest position) so -.39 = .39*sin(phi) -1=sin(phi) sin^-1(.1)=phi -90=phi But using -90 for phi I still get the wrong answer, can anyone confirm that that is the right way to get...

Homework Statement A block of mass 0.678 kilograms is suspended from a spring with a spring constant of 28.6 Newtons per meter. When the block is at rest, it is located 1.44 meters above the floor. The block is then set into oscillation by being lifted to a height of 1.83 meters and...