Recent content by BlueRope

Homework Statement equation of line 1: (x-2)/2 = (y+6)/3 = (z-a)/-1 equation of line 2: (x+4)/5 = (y-6)/b = z-3 both lines are perpendicular to each other AND are in the same plane (coplanar) ALSO find the equation of the plane Homework Equations The Attempt at a Solution...

If you already have one of the two coordinates?

Yeah, why is that?

What are those two ways?

Homework Statement vector a = (0,1,0) vector b = (-2,1,1) vector c = (1, a-2, a+2) for what value of a are the three vectors coplanar? Homework Equations don't know how to do this The Attempt at a Solution didn't try anything

A necessary and sufficient condition for three vectors to be coplanar is the equality is that the determinant of the matrix equals zero.

Why does the half of the absolute value of a matrix formed with its coordinates give the area of a triangle? I don't see any similarity between that and the heron's formula.

I finally understood how he did it. However, I don't understand how it answers the question. He wanted the values of b and a, but we only got the value of k. If the answer is 7(a-1) vector z then a GENUINE answer would be: b = 0 and a = R or any value, right?

Basically, he wrote 6a -b -4 = 0 then he isolated b, which gives: b = 6a -4 then he somehow came with the answer, which is, like I said: t = 7(a-1)(-3,4) or 7(a-1)vector z. I have no idea what the teacher did.

I was thinking of doing that, until I saw the answer, which was t = 7(a-1)(-3,4) or 7(a-1)vectorz.

Homework Statement For what values of a and b are these two vectors collinear (linear algebra)? t = (3a -4b +5, 5b -2a -8) v = (-3, 4) t and v are vectors Homework Equations The Attempt at a Solution I'd like to know what the steps are. I don't really care about the answer.