Recent content by bob1182006

So this device is going to be able to decompose music into the fundamental pitches and display it in real time, sort of how a trained ear can listen to music and determine which notes to play on an instrument? Seems like an interesting product and great project. You might also want to speak...

I don't have Scilab but I think your problem is that T is calculated by matrix division not an element by element division. Other than that it seems like the code should work fine. Try: T = 1 ./(1+0.36 .*(sinh(delta)) .^2)

These are the four types of signals: 1st one you got right, continuous time continuous value 2nd one is a discrete time continuous value. The lines are just there to make it easier to see at what time each point represents. In MatLab you make those plots by using stem(x,y). 3rd one is a...

Could you link a picture or attach one showing what you mean? If you mean how most of the traces (copper left after etching out the surrounding) make a lot of angled turns, no curvatures, then that's done to try to keep the impedance of the line constant at the turns. Also the traces can't...

Your y is only 1 value at the end change your ))/x to ))./x and your graph comes out correctly. Also you might want to change your starting index from 0 to 0.01, since you get y(1) = NaN. The plot still comes out correctly but if you're doing anything else with y you will run into problems.

Make an array for each k1/2/3/.../10 to hold all of the values and change your loop so as you iterate from 1:N you go through different columns of k1/2/.../10. For ex. N=32; count=1; k10 = zeros(1,N) K10(1) = input('Enter the value of intial k-10: '); while count<=N % Check...

Awesome thanks, I didn't want to waste any more time redoing this problem looking for a mistake, and my class is just starting the thermal resistance chapter so if I see more problems that have wrong answers I'll do them that way to check. We're using Heat and Mass Transfer Fundamentals &...

Homework Statement Consider a large plane wall of thickness L = 0.4m, thermal conductivity k = 1.8W/(m*K), and surface area A = 30m2. The left side of the wall is maintained at a constant temperature of T1 = 90 C while the right side looses heat by convection to the surrounding air at Ts = 25...

Ah, sorry I thought it was all in the denominator. For that one all I think of is a trig substitution, which isn't my best area. But looking at it I'd think you want to try x = 5 sqrt(2) sin(u) so that you can get rid of the root into a cosine.

The x's don't cancel outside of the 3/2 root. The second step would be to do a substitution of everything inside the 3/2 root. \int \frac{1}{3x^2x^3(50x^{-2}-1)^{3/2}} dx u = 50x^(-2) - 1

Take out (x^2) from the denominator's root. \int \frac{1}{3x^2(50-x^2)^{3/2}}dx = \int \frac{1}{3x^2x^3(50x^{-2}-1)^{3/2}} dx

Start out by taking out x^2 to get \frac{1}{x^2x^3(50x^{-2}-1)^{3/2}}

I think you need to take into account the ball's velocity after colliding with the ground. Also you're saying vf = 1.2m/s but the problem states that vi = 1.2m/s. To find vf you need to use the information about the gravitational potential energy.

It should be: header(1) = {'Jill'}

What are the graduate students that you work with doing? A lot of drafting like you? I think as you spend more time working there you would start to be assigned little projects/calculations to do that require some information that you learned in school. But if the graduate students are mainly...