Impulse imparted by the ground on the ball?

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SUMMARY

The impulse imparted by the ground on a 100.0 g ball dropped from a height is calculated using the formula for impulse, which is impulse = m(vf - vi). The initial velocity (vi) is 0 m/s at the moment of impact, while the final velocity (vf) is 1.2 m/s. The calculated impulse is 0.12 kg m/s. However, the discussion highlights the need to consider the ball's rebound velocity, which is influenced by its gravitational potential energy, as it rebounds to 78% of its initial height.

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Homework Statement


A mass 100.0 g is dropped from some height above the ground and rebounds to a point where it has 78% of its initial gravitational potential energy. As it hits the ground, it is moving at 1.2 m/s. What is the impulse imparted by the ground on the ball?


Homework Equations


impulse = m(vf-vi)


The Attempt at a Solution


impulse = (0.1)(1.2 m/s - 0 m/s)
=0.12 kg m/s

I followed the formula for impulse, but i feel like I did it wrong because there was a lot more information given in the problem that I didn't use in my solution
 
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I think you need to take into account the ball's velocity after colliding with the ground.
Also you're saying vf = 1.2m/s but the problem states that vi = 1.2m/s.
To find vf you need to use the information about the gravitational potential energy.
 

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