Recent content by Bob_Dole

Constructive and destructive interference I presume. You can draw it, we did this in first year undergrad.

Yep, surely I was not using my noggin! Thanks again for your help. I got the correct answer just by subtracting the two.

The fact that the object "falls" toward the surface, would indicate that gravity is supplying more acceleration (greater than the fictitious centrifugal force). Thus, I need to find out by how much. This would be 10 \,\, m/s^2 - 9.3 \,\, m/s^2 = 0.3 \,\, m/s^2 . I am now embarrassed. Thanks...

Centripetal acceleration of course, which would have some velocity perpendicular to this acceleration.

Homework Statement Determine the length of day on a planet. Imagine a planet with an acceleration at the equator of a_{equator} = 10 \,\, m/s^2 (ignoring rotation). Object dropped at equator falls with an acceleration of: a_{obj} = 9.7 \,\, m/s^2 , r = 6.2 \times 10^6 \,\, m ...