Recent content by bodkin.thomas

Thanks for your help tonight! Made a mistake typing the matrix in my calculator... :redface:

How about these? I1 = 18.0 I2 = 3.8 I3 = 3.8 I4 = 10.5

Alright, here's another attempt... I1 = ~ 18.0 I2 = ~ 1.79 I3 = ~ 1.79 I4 = ~ 14.5 What I did might work or I might have done something illegal... I took 55-7I2-2I3-2I4 -20 -5I3+2I4 -5I2+5I3 added them and got 35 - 12I2 -2I3 = 0 and then solved for I3 I3 = 12.5-6I2 Then I...

Well there's one problem. I wasn't sure how the rule would function in this case because there were four currents. I'll give it another try with that new rule and come back when I have something to show.

Here's what I did http://dl.dropbox.com/u/9172399/Pictures/001%20%282%29.jpg

Ok, solving the equations, I got the following I1 = ~ 12.2 I2 = ~ 6.11 I3 = ~ 6.11 I4 = ~ 25.3 So now, using P=IV, can I simply substitute the I values I got above and the voltage that the provide in each part? Or is it not that simple?

Homework Statement Here is the accompanying diagram. Calculate the power delivered to each of the resistors in Figure P28.28 (E = 55 V, R = 5.0 .) ____W (2.0 resistor in loop with 55 V source.) ____W (5.0 resistor in loop with 55 V source.) ____W (5.0 resistor in loop with 20 V...