Recent content by brentwoodbc

Ya from the center of the earth, somebody else mentioned it but I still get the wrong answer, its getting closer though...but still wrong.

Thank you.

I have Fc=2895 and Fp=2541 F_p is the answer correct?

Yes its 2600 I am still kind of confused. so you find the ratio between Fpost and F cable In one of the equations and plug it into the other? then what does the force on x =? post -/+ cable?

This question BUGS me I've tried it a whole lot of times, my teacher explained it to me at least 2 times but he came up with the wrong answer. I had a couple class mates explain it but it was an Extremely long/condusing way of doing it. I know the x components are equal so there is no x...

yeah I forgot about the Earth radius I keep getting 4.36E10 though.

Start Etotal=1/2mv^2 + (Gm1m2)/r 1/2•1600•(7E3)^2 (6.67E-11•1600•5.98E24)/(100•1000) Etotal=6.36E12 Final Etotal=EP+EK 6.36E12=(6.67E-11•5.98E24•1600)/(400•1000)+EK EK=4.82E12 ? whats wrong?

so at the start is velocity the 7E3 or is that the average velocity Ive tried finding Etotal at the start and at the end and subtract one from the other but I always get the wrong answer.

I read that the change in potential is = work/energy and since velocity is constant EK is constant. but when I use the formula for ep I don't get the right answer.

heres a pic... also would solving this be similar to how you would find the heat lost from a resistor in a circuit because I had a question like that and I couldn't solve it.

thank you very much.

or do u use 250j total energy and the inititial Ep, I thinks that's right.

ya there is ep and ek but you can't really find Ek at the start or at the end right? unless you assume the starting velocity is 0 but what if its not?

I did f=ma (30+20)/2=2a a=12.5m/s^2 vf^2=vi^2+2ad vf^2=0+2•12.5•10 vf= 16 m/s I remember doing a question like this on a test a while ago and I think the teacher said you don't know that the initial velocity is 0 or something like that? anyways my way I don't get the right...

how do you do heat energy questions? is it the energy lost? An unpowered 1600 kg object has an upward velocity of 7.0 x 10^3 m s at an altitude of 100 km above the earth. The object reaches a maximum altitude of 400 km. Earth 100 km 400 km v = 7.0 × 10^3 m s What is the heat energy...