Recent content by buraqenigma

Yes, i know the simplest way is image method ,but we want to find any solution of poisson equation for this problem.And the intersting point of this problem is the q charge is inside grounded sphere (a<R). I have soltion for any charge outside sphere(a>R) but i don't know difference bettween...

Yes it's grounded (the word that i'cant rememeber) sphere.Thanks for good starting point Niles .I'll come back with my solution [ P(x,y,x) must be P(x,y,z) ]

notr mean sphere has no charge

There is +q charge in a notr sphere that has a radius R and center is located on the origin.Location of the charge is (0,0,a) (a<R).Calculate the electrostatic potantial of any P(x,y,x) point outsite sphere 2. Homework Equations is poisson equation \nabla^{2}u=\rho(x,y,z)3. I can't start from...

Can anybody explain me the conditions for become a beta decay. for example : Md (Z=101,A=255) --> No (Z=102,A=255) + e (electron) + -Ve (anti-notrino) can this nuclear reaction be?

if we know \left[\hat{p}_x,\hat{x}\right]=-i\hbar we can show this equation. Thanks my friends for your helps.

is this regular ? \left[\hat{p_{x}}^2,\hat{x}\right]=\left[\hat{p_{x}},\hat{x}\right]\hat{p_{x}}+\hat{p_{x}}\left[\hat{x},\hat{p_{x}}\right] ( from leibniz rule)

How can we show \left[\hat{H},\hat{x}\right]=\frac{-i\hbar}{m} \hat{p_{x}} ?

Thanks sir. Thanks sir ,I agree with you.This DE. can be solved by using power series solution method.

Yes ,But? Main question is, if i don't know the eigenfunction in the beginning ,how can i find the eigenfunction of operator A ? i can't solve the de. \frac{d^{2}u(x)}{dx^2}-x^{2}u(x) = a u(x) help me ?

Like This ? Is this true? \frac{d^{2}u(x)}{dx^2}-x^{2}u(x) = a u(x) u(x) is the eigenfunction and a is eigenvalue for this function

How can i prove that u(x)=exp(-x^{2}/2) is the eigenfunction of \hat{A} = \frac{d^{2}}{dx^{2}}-x^2 .(if i don't know the eigenfunction how can i find it from expression of A operator)

Thanks sir. thank you i remember it .

How can i prove that u(x)=exp(-x^{2}/2) is the eigenfunction of \hat{A} = \frac{d^{2}}{dx^{2}}-x^2

Explaining if A is lineer operator A[af(x)+bg(x)]=aAf(x) + bAg(x) x is the parameter of functions in Hilbert space