I was wondering exactly where you started in the file.
It looks like you started around https://www.physicsforums.com/showpost.php?p=1129304&postcount=6.
l^2cos^2(theta) - 2beta*c*tau'*l*cos(theta)gamma + [l^2{1-cos^2(theta)}]gamma= c^2tau'^2
l^2cos^2(theta) - 2beta*c*tau'*l*cos(theta)gamma + [{l^2-l^2cos^2(theta)}]gamma= c^2tau'^2
What do I need to do to get the below?
At some point, I need to combine the cos^2 terms.
"quadratic
0 =...
Could you give some more detail on "length contraction in the x direction to figure out the coordinates of P in S' when the pulse is" emitted?
l= l_p/gamma
Also,
(c*tau')^2=(v*tau')^2+(x)^2 ?...
A flash of light is emitted at point O and is later reabsorbed at point P. In frame S, the line OP has a length l and makes an angle theta with the x axis. In a frame S' moving relative to S with a constant velocity v along the x axis:
How much time tau' elapses between emission and absorption...
A particle of rest mass m. and kinetic energy 2m.c^2 strikes and sticks to a stationary particle of rest mass 2m.. Find the rest mass M. of the composite particle. (.=zero subscript)
The answer is (17)^1/2(m.)
4 x 10^9 eV / 931.49 x 10^6 eV = 4.3 amu (should there not be a /c^2 in the conversion information?)
I'm trying c now.
v/c = cp/E
v=c^2p/E
v. = c^2(3 GeV/c) / 4 GeV = 2.25x10^8 m/sec
v=2.12x10^8 m/sec
I got u= 2.86x10^8 m/sec...