Recent content by byronsakic

Hello, here is the question. Two masses, 4.0 kg and 6.0 kg, are connected by a “massless” rope over a “frictionless” pulley as pictured in the diagram. The ramp is inclined at 30.0º and the coefficient of kinetic friction on the ramp is 0.18...

i got the answer by using coordinate proofs and making LS = RS thanks for all your help :D

didnt i do it in the first try? but if you drop a perpendicular from A to line segment BC then how would u prove that it is a right angle? but i think i did that in first try.. though i am going to try coordinate proofs right now :D i think that is the solution

Hello, Here is the question: Here are 2 different ways i tried to approach the question: In the first way, i tried using pythagoreom theorem by making a right angle, but after i did the question i realized since it did not say it was a right triangle, ic annot assume there is a 90 degrees...

thank you very much i got it :D

Hello, i am having difficulty on a question involving chords i believe. what i have so far is: the length of CA is 17. therefore the length of CB is also 17 due to the fact that it is the radius of the first circle. the length of AD is 10. Therefore BD is also 10 because it is the radius...

thanks a lot :D

any further suggestions? like this is a question we've never seen before so i don't know how to approach the question, using a scalar a = kb with the s would give me k and s right. but i have to solve for s.

the vectors u and v are linearly independent. find s, if vectors (1-s)u - 2/3v and 3u +sv are parallel. i got them equal to each other...but then if you draw them, both of them would be in the exact place which makes them collinear...so would you say it is parallel because vectors u and v are...

alright thanks

The Cosine of the angle between a and b is 4/21. Find p if a = 6i + 3j -2k and b = -2i + pj - 4k. i started off with the general equation a . b = |a| |b| cosX where cosX is 4/21 since i, j, k all mean 1. i would get two vectors a = (6,3,-2) and b = (-2, p, -4) then i would take the...

but u and v are coplanar? XD

the vectors u and v are linearly independent. find s, if vectors (1-s)u - 2/3v and 3u +sv are parallel. where u and v are vectors. i am totally clueless, even my tutor couldn't solve it.

yes, so if i divided it into x and y components, i would be using cartesian vectors right? instead of geometric vectors

bah i am actually now confused in why the 320 km/h or planes speed is the resultant vector. Wouldnt 320 km/h be the S 40 DEGREE W vector in the third quadrant? is there anyone else who would think there would be an alternative way ? XD my first approach would to think to use the...