I must be, because when I construct the diagram, the location of the second image is neither 30 cm in front of or behind the second lens, which doesn't lend our answer much levity.
Homework Statement
A 2 cm tall object is 20 cm to the left of a lens with a focal length of 10 cm. A second lens with a focal length of 15 cm is 30 cm to the right of the first lens. Calculate the image position and height. Compare with ray-tracing.
Homework Equations
1/f = 1/do + 1/di, m =...
And for others,
First 5=10e^-(bt/2m), 5/10=e^-(bt/2m), ln(1/2)=-(bt/2m), solve for t, t=(2mln(1/2))/-b, substitute given values, [2(0.120)ln(1/2)]/-(0.0180)=t=9.24 seconds.
Well. I found the equation that works.
final amplitude=original amplitude times e raised to the quantity of -(bt/2m) where b represents the damping constant, t the amount of time, and m the mass of said device. And after that it's pretty basic math. If this could be derived from the...
I think I understand what you're saying. So start with a standard equation, then take the derivative producing two other equations, and substitute the given values in front of each of the respective equations. Is this correct?
Homework Statement
A spring with a force constant of 1.50 N/m is attached to a mass of 120 g. The system has a damping constant of 0.0180 Ns/m. How long does it take the amplitude of the oscillations to decrease from 10.0 mm to 5.00 mm?
Homework Equations
(double dot)x +(c/m)(one...
Homework Statement
A ferris wheel with a radius of 14.0 m rotates at a constant rate, completing three revolutions in 50.0 s. What is the apparent weight of a 60.0 kg passenger when she is at the top of the wheel?
Given choices: 532 N, 452 N, 562 N, 625 N, 469 N
Homework Equations...