Recent content by canadianballa

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    Electric potential with charges

    Thanks guys for your help. I'll work on solving it now and post the attempt in a bit.
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    Electric potential with charges

    Homework Statement Two charges are placed at the corners of a square. One charge, +4.0uC, is fixed to one corner and another, -6.0uC is fixed to the opposite corner. WHat charge would need to be placed at hte intersection of the diagonals of the square in order ot make the potential...
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    Help Solving Momentum Problem with 3 Kids and a Cart

    Mcx + M3k gVk = Mcy+ m2k gVk' 0 = 120 kg y + 120kg (cvk' + y) y = 5 m/s which is wrong, cause the cart's supposed to be moving FASTER. which is where I'm stuck
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    Help Solving Momentum Problem with 3 Kids and a Cart

    I just assumed that the system starts @ zero, so... Mcx + M3k gVk = Mcy+ m3k gVk' 0 = Mcy + m3k gvk' 0 = 120kg y + m3k (cVk + y) find that the system is moving @ 6m/s. Where I'm stuck is...how do I find the speed of the cart after one of the kids jump off? I figured that since mass is...
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    Help Solving Momentum Problem with 3 Kids and a Cart

    Based on the numbers, I find that 120kg * 6m/s + (180 kg * (-10m/s-6m/s) = zero which doesn't make any sense and it's where I'm stumped. Based on this, the system is initially not moving?
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    Help Solving Momentum Problem with 3 Kids and a Cart

    Could somebody please point me in the right direction?
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    Help Solving Momentum Problem with 3 Kids and a Cart

    I'm going to use the following denotations (it's easier to type) x= gVc (initial Velocity of cart relative to ground) y = gVc' (final velocity of cart relative to ground) Mc = mass of cart M3k = mass of 3 kids, 2 kids, etc gVk = cVk + gVc (velocity of kids relative to ground = kids velocity...
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    Help Solving Momentum Problem with 3 Kids and a Cart

    Hello everyone, My teacher posted this question and I've been having problems solving it. Please help. Homework Statement 3 kids are standing on top of a cart. The cart is on top of a frictionless surface. The kids run WEST at a maximum of 10m/s. As such, the cart will be pushed in the...
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