Recent content by canadianballa

Thanks guys for your help. I'll work on solving it now and post the attempt in a bit.

Homework Statement Two charges are placed at the corners of a square. One charge, +4.0uC, is fixed to one corner and another, -6.0uC is fixed to the opposite corner. WHat charge would need to be placed at hte intersection of the diagonals of the square in order ot make the potential...

Mcx + M3k gVk = Mcy+ m2k gVk' 0 = 120 kg y + 120kg (cvk' + y) y = 5 m/s which is wrong, cause the cart's supposed to be moving FASTER. which is where I'm stuck

I just assumed that the system starts @ zero, so... Mcx + M3k gVk = Mcy+ m3k gVk' 0 = Mcy + m3k gvk' 0 = 120kg y + m3k (cVk + y) find that the system is moving @ 6m/s. Where I'm stuck is...how do I find the speed of the cart after one of the kids jump off? I figured that since mass is...

Based on the numbers, I find that 120kg * 6m/s + (180 kg * (-10m/s-6m/s) = zero which doesn't make any sense and it's where I'm stumped. Based on this, the system is initially not moving?

Could somebody please point me in the right direction?

I'm going to use the following denotations (it's easier to type) x= gVc (initial Velocity of cart relative to ground) y = gVc' (final velocity of cart relative to ground) Mc = mass of cart M3k = mass of 3 kids, 2 kids, etc gVk = cVk + gVc (velocity of kids relative to ground = kids velocity...

Hello everyone, My teacher posted this question and I've been having problems solving it. Please help. Homework Statement 3 kids are standing on top of a cart. The cart is on top of a frictionless surface. The kids run WEST at a maximum of 10m/s. As such, the cart will be pushed in the...