Recent content by Carbon123

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    Heat Capacity relations for 1st order phase transition

    Homework Statement Prove the following relation for which clausius equation holds : Cs=Cp-αV(ΔH/ΔV) Where Cs=∂q/∂T at constant S and is the heat capacity in the coexistence line of 2 phases Homework Equations dq=dU+dW dP/dT=ΔH/(ΔV*T) The Attempt at a Solution I do not fully understand why q...
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    Understanding the Arrow Notation in Organic Chemistry Elimination

    Can anyone help me with this ? What does the arrow mean ? Is it cis or trans,the base is small so it should be an E2 elimination with zaitsev product.Though I think it may be due to the beta hydrogen being unavailable,but I do not know whether the arrow means from the upper or lower /cis trans...
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    Identifying the Source of Organic Chemistry Problems: A Scientist's Perspective

    Welp,now that was stupid.I thought I uploaded the pic (note :sorry for the bad quality and the writings)
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    Identifying the Source of Organic Chemistry Problems: A Scientist's Perspective

    Hello ! I am preparing for chemistry olympiad,and my friend gave me this exercise in organic chemistry,but he won't tell me what book this is from can anyone help identify what book /problem collection this is ? (It has got some nice problems,at least higher than solomons organic chem) Thanks in...
    • Carbon123
    • Thread
    • Book Chemist Chemistry Organic
    • Replies: 2
    • Forum: Chemistry
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    Rolling Cylinders across a grid of bars

    Oh,then plus Iω on the left side and Iω' on the left
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    Rolling Cylinders across a grid of bars

    MωRcos2Θ×R is angular momentum around point B .angular momentum after is going to be Mω'R×R ?
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    Rolling Cylinders across a grid of bars

    So that would mean Wrcos2Θ
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    Rolling Cylinders across a grid of bars

    Here is the image
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    Rolling Cylinders across a grid of bars

    Why wpuld it be wrong ? Please point it out, sir
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    Rolling Cylinders across a grid of bars

    Angular momentum before the collision will be Iω+MVRcosΘ=Iω'+MvRcosΘ where v is total linear speed. What should i do next ?
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    Rolling Cylinders across a grid of bars

    Oopa i thought I had typed it. What I meant to say was the speed will be ωR and the direction is perpendicular to the line connecting center of mass and left bar,with ω being rotation wrt to the bar.(Now that i think of it ,it seems incorrect ) After the collision only the horizontal component...
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    Rolling Cylinders across a grid of bars

    Before the collision ,The linear velocity of the cylinder should be perpendicular to the bar on the left.I imagine as if the cylinder rotates around an axis that is the bar,therefore the speed is or is this wrong ?.If i consider it as a normal cylinder motion then the cylinder will have...
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    Rolling Cylinders across a grid of bars

    I am quite confused,sir.What do we need to know is he loss in energy after every collision right ? So what is the next step I should do ?
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    Rolling Cylinders across a grid of bars

    Iωο=Iω with I being around the pont of contact.This equation doesn't really make sense considering the inertia is the same around the contact points,therefore the omega is constant (?)
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    Rolling Cylinders across a grid of bars

    On the point of contact,is the angular momentum conserved ? But there is a force creating torque around the point.For the velocity ,here is what i think.The cyllinder will rotate around the bar so kinetic energy will be 1/2 I ω2 where I is moment of inertia around point of contact. So the...
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