Here is the question...Two boats are heading away from shore. Boat 1 heads due north at a speed of 3 m/s relative to the shore. Relative to Boat 1, Boat 2 is moving 40° north of east at a speed of 1.7 m/s. A passenger on Boat 2 walks due east across the deck at a speed of 1.1 m/s relative to...
I came up with :
x0=0
x=?
v0x=16.5cos55
vx=
ax=0
t=?
y0=0
y=2.1
v0y=16.5sin55
vy=
ay=-9.8
t=?
I solved for time and then i solved for x...i came up with 13.5/2.2
which gives me an answer of 6.1 m/s...which is wrong
i subtacted the .3 and the 10 m before i divided them too...it...
I have tried what you suggested, but I am unsure as to what exactly imsolving for in each equation?? I need help with my given variables and my unknowns
Here is the problem...The lob in tennis is an effective tactic when your opponent is near the net. It consists of lofting the ball over his head, forcing him to move quickly away from the net (see the drawing). Suppose that you loft the ball with an initial speed of v = 16.5 m/s, at an angle of...
Thank you very much for all your help...its greatly appreciated!...Ill try these numbers and see what i get. I hope to see you on here again if i have more questions down the road.
well like i said, i started with Vy*2= Voy*2 + 2a (Y-Yo)
so i plugged in numbers...(8.5)*2= Voy*2 + 2(-9.8)(-3-0)
and i got 13.45=Voy*2
for an answer of Voy= 3.66
well i came up with a y-component of the initial velocity= 3.66 m/s
then i used Vy=Voy + at to find time
but i came up with -.49...?
so i tried plugging that into find the initial velocity of x-component...using V= Vo +at...but i got 2.6?
That isn't right...:(
So those answers i came up with were wrong?
Im sorry...I thought that was what i was to find, in the previous step?
Im sorry, i am confusing myself big time
I tried finding the arccos and arcsin...but it doesn't seem right.
I got arcsin= 9.3 and arccos = 30.4.??
And after i find those (when i get them right), ill have
y initial= 0
y final = -3
velocity component of y = (whatever the correct answer from above is)
velocity component of x= ( "...
Here's what i think is going on so far:
y initial =0
y final = -3
I am trying to draw a triangle to solve for the info I am giving about her speed of 8.9 m/s and the angle with respect to the horizontal which is 73 degrees.
But isn't her speed...gravity, -9.8 m/s 2??
I have tried...