Tennis Lob question Very confusing

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    Confusing Tennis
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The discussion revolves around calculating the minimum average speed a tennis player must achieve to hit a lobbed ball. The lob is launched at an initial speed of 16.5 m/s at a 55° angle, with the player starting 10 m away and moving 0.30 seconds after the ball is hit. Participants express confusion about setting up the equations of motion for both the ball and the player, particularly in determining the correct variables and unknowns. Calculations for time and distance are shared, with one participant arriving at an incorrect speed of 6.1 m/s, while another suggests the correct answer is 6.34 m/s. The thread emphasizes the importance of careful calculations and understanding the motion equations involved.
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Here is the problem...The lob in tennis is an effective tactic when your opponent is near the net. It consists of lofting the ball over his head, forcing him to move quickly away from the net (see the drawing). Suppose that you loft the ball with an initial speed of v = 16.5 m/s, at an angle of = 55.0° above the horizontal. At this instant your opponent is 10.0 m away from the ball. He begins moving away from you 0.30 s later, hoping to reach the ball and hit it back at the moment that it is 2.10 m above its launch point. With what minimum average speed must he move? (Ignore the fact that he can stretch, so that his racket can reach the ball before he does.)
m/s
Alot of information...where to start?? I know it is a multiple step problem, but how to go about starting it has me puzzled.
Any help giving me a direction on how to tackle this would be appreciated.
 
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Write the 2-D equations of motion for the ball, and the 1-D equation of motion for the tennis player.
 
I have tried what you suggested, but I am unsure as to what exactly imsolving for in each equation?? I need help with my given variables and my unknowns
 
Please show your work here, so that we can try to help you.
 
I came up with :
x0=0
x=?
v0x=16.5cos55
vx=
ax=0
t=?

y0=0
y=2.1
v0y=16.5sin55
vy=
ay=-9.8
t=?
I solved for time and then i solved for x...i came up with 13.5/2.2
which gives me an answer of 6.1 m/s...which is wrong
i subtacted the .3 and the 10 m before i divided them too...it comes out with the wrong answer...??
 
check ur calculations when i tried doing it i got 6.34m/s not 6.1m/s
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .

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