willem2 thanks for your response.
that is one of the example in my book.
can you please explain it a little bit more. maybe a step by step?
please.
how come that all the L are gone and the W are only 2 then it becomes 3. i will appreciate it very much.
can you please explain why this
(TLsin30.0° − w((L/ 2)cos30.0°) − w(Lcos30.0°) = 0)
becomes this
T sin30.0° − (3w/ 2)cos30.0° = 0
i though i can do all the transpose and other stuff. but i can't figure that one.
i want to get the T.
please help me.
Homework Statement
Please help me to draw free body diagrams of the following.
1.Find the tension T in each cable and the magnitude and direction of the force exerted on the strut by the pivot in each of the arrangements in fig. 11.23 in each case let w be the weight of the suspended crate...
Homework Statement
an antelope moving with constant acceleration covers the distance between two points 70.0 m apart in 7.0 s. Its speed as it passes the second point in 15.0 m/s .
a) what is its speed at the first point?
b)what is the acceleration?
Homework Equations
what do you...
you mean like this?
the truth is i only know how to get the other angles but i don't know where toplace them.
thanks for the information now i know where to place them.
is this correct?
http://img341.imageshack.us/img341/1923/41728774.png http://g.imageshack.us/img341/41728774.png/1/...
ow I am sorry.haha!
i forgot to tan-1 it..
the answer = 56.31 deg.
:)
for this question
c(->) = 125m/s 75deg north of east
e(->) = 500 kg m/s (hey, what should i do in that kilogram meter/second? thatas what makes me confuse) 18 deg south of east.
s(->) = 707m 26 deg west of...
for letter a. i just subtract the 800N. with 600N. so i the answer will be 200N south. :)
thanks for clarifying my answer. the theta for letter b. will be 0.03 right?
450/300 = 1.5
tan(1.5) = 0.03..
im pretty sure that I am correct.
thanks now i know..
heres the question:
thanks modulus, thanks tiny-tim. I am more sure of my answer by now.
for a) 800N. due south and 600N. due north. i think i don't need to find the theta.
because it will be like these.
...800N due South.
..^...l
..l...l
..l...l
..l...l...
so it mean that iam correct? o:)
by the way.. what is the easiest clue for me to know what is the adjacent and opposite.
its easy to know the hypotenuse but i don't have any clue on how to know the adjacent and opposite.
thanks modulus, thanks tiny-tim. I am more sure of my answer by now.
for a) 800N. due south and 600N. due north. i think i don't need to find the theta.
because it will be like these.
...800N due South.
..^...l
..l...l
..l...l
..l...l
..l...V
600N due North
the answer will be 200N...
ow. sorry for that.
after researching on how to get angle for right triangle i m pretty sure this is correct.
C= 125 m/s 75 deg North of East
http://img228.imageshack.us/img228/8565/69844695.th.png
is this correct?
am i wrong in my answer 111.80?
i though that i will need to...