Recent content by cashmerelc

1 atm?

Okay, if you have 1 kilomole of ice melting at 0 C and you have a given latent heat of fusion of ice as 3.348 x 10^5 J/kg and the density of ice as 917 kg/m^3 and te density of water as 999.9 kg/m^3, I don't understand how to find the work done. I know that work done is PdV, so it should be...

/facepalm I always forget implicit differentiation. Thanks a million, HallsofIvy!

This is the original equation, which is given: P=(RT/v-b)e^(-a/RTv) I have to find the partial derivative of T with respect to v. This is what I'm saying my problem is. I am trying to separate T out so I can write the equation as a function of T. Here is what I have... T=...

Well, that's what I'm having trouble with. I have to take dT/dv keeping P constant. So I need to get all of the Ts on one side of the equation. The problem I'm having deals with the T in the exponent. I know to solve for a variable in an exponent of e, you take the ln of both sides. But...

I have to find the expansivity of a substance obeying the Dieterici equation of state using the cyclical relation. I understand what I need to do, but I'm having a problem with the partial derivatives of the equation of state. I was wondering if anyone could refresh me on how to take a...

In this case, you don't have to find fz. Z itself is f(x,y). The value for z comes from plugging in the values for x and y into the equation which gives you z.

Okay, I think one more question will help me get it. \delta_{jk}\delta_{kj} = ?

If \delta_{ij}\delta_{jk} = \delta_{ik} does that mean that \delta_{lk}\delta_{kj} = \delta_{lj} and so on?

Homework Statement Prove \sum_{j,k} \epsilon_{ijk} \epsilon_{ljk} = 2\delta_{il} Homework Equations \epsilon_{ijk} \epsilon_{ljk} = \delta_{il}(\delta_{jj}\delta_{kk} - \delta_{jk}\delta_{kj}) + \delta_{ij}(\delta_{jk}\delta_{kl} - \delta_{jl}\delta_{kk}) + \delta_{ik}(\delta_{jl}\delta_{kk} -...

I finally understand it. It's a miracle :) Thank you guys very much for your help with this.

And thank you guys for being patient. Sometimes I think so hard about things that I miss the point altogether

Alright, I should've known that was the equation of a plane. My mind is growing numb. Okay, I think I am finally grasping it. I understand that one way of stating A . B is the projection of vector A onto vector B multiplied by the magnitude of vector B. So if you have A . B where...

It looks like the equation of a line in three dimensions

A.R = AxRx + AyRy + AzRz = k