Recent content by Castiel

Hmmm so I'd use this equation? [H+]=Ka [HA]/[A-] ? Then to find the concentrations, could I just do... (2.28g H+) X (1 mol/76.11 g) = .02996 mol H+ and for one liter-----> [H+]=0.02996 and (1.96g A-) X (1 mol/76.11 g) = .02575 mol A- and so [A-]=0.02575 meaning... 0.02996=Ka [HA]/.02575 ? But...

Homework Statement Suppose you wish to determine Ka for a monoprotic weak acid of molecular mass 76.11 g/mol. The pH meter you need to use is not working. You decide to weigh out 2.28 g of the acid and 1.96 of its sodium salt and dissolve them together in water, add quinhydrone and set up a...

Homework Statement A mass m is dropped from a height H onto a hard, flat surface. When it collides with the surface, it rebounds with the same speed it had before the collision. However, there is a constant force of air resistance f acting on the mass as it undergoes this motion. Answer the...