Recent content by castrodisastro

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    Find the period of small oscillations (Pendulum, springs)

    Sorry I was using the Voice to Text feature on my phone and I said "theta" but it heard me as saying SATA. Ok let me get back to the drawing board and respond to your suggestions tomorrow. Thanks
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    Find the period of small oscillations (Pendulum, springs)

    Ah I see what you mean... Since my restoring torques rely on the displacement then if I look at my system when the rod is pointing straight down then there wouldn't be any restoring torques present, but if I choose a different configuration then that means there is some displacement and so I...
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    Find the period of small oscillations (Pendulum, springs)

    Yes, I meant restoring torques, my mistake. From what I read the moment of inertia of a uniform rod is 1/12mr^2. Since it is pivoting about a point that is a displacement L/2 from the center of mass then the moment if inertia becomes 1/3mr^2 via the parallel axis theorem. And to answer your...
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    Find the period of small oscillations (Pendulum, springs)

    Homework Statement A uniform rod of mass M, and length L swings as a pendulum with two horizontal springs of negligible mass and constants k1 and k2 at the bottom end as shown in the figure. Both springs are relaxed when the when the rod is vertical. What is the period T of small oscillations...
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    Taylor series expansion of an exponential generates Hermite

    Ah ok I got it! I must have been making mistake when taking numerous derivatives. Thank both of you.As for the comment I had made about being berated, I think that because I am forced to type this out, as opposed to speaking, it is difficult to imitate the rude way that some tutors speak to...
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    Taylor series expansion of an exponential generates Hermite

    Homework Statement "Show that the Hermite polynomials generated in the Taylor series expansion e(2ξt - t2) = ∑([FONT=Book Antiqua]Hn(ξ)/n!)tn (starting from n=0 to ∞) are the same as generated in 7.58*." 2. Homework Equations *7.58 is an equation in the book "Introductory...
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    Where Does a Particle Reflect in a One-Dimensional Potential Field?

    Homework Statement A particle constrained to move in one dimension (x) is the potential field V(x)=[(V_0(x-a)(x-b))/(x-c)^2] (0 < a < b < c < infinity) (a) Make a sketch of V (b) Discuss the possible motions, forbidden domains, and turning points. Specifically, if the particle is known to...
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    Prove that s^2=(s')^2 using the Lorentz Transformation

    Homework Statement I am learning special relativity and we came across the invariant quantity s = x2 - (ct)2. Our professor wants us to prove it. I admit that this is a proof and belongs in the mathematics section but I didn't see an Algebra section and this is most easily identified by those...
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    General solution of a system of diff eq's.

    I see. Would my \vec{w} then still be the same? I assume it would just be written in the second form that I stated.
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    General solution of a system of diff eq's.

    Ok, that makes sense. So I must have missed that one sentence, IF he said it. So then my eigenvector is \begin{bmatrix} 1\\ 0\\ \end{bmatrix} All that is left is to find the second eigenvector, \vec{w}. Now I set (λI-A)\vec{w}=\vec{v} Solving for \vec{w} gives me the vector...
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    General solution of a system of diff eq's.

    Homework Statement Find the general solution of y'=Ay. Your answer must be a real-valued function. A= \begin{pmatrix} 1 & 1\\ 0 & 1\\ \end{pmatrix} Homework Equations The Attempt at a Solution The first step would be to find the eigenvalues. I forgot the name of the term but if...
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    Thin lens equation and image formation

    I should not have used the approximation symbol, that was my mistake in expressing the values. I do need to do a better job of using significant figures correctly. Thanks for mentioning it.
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    Thin lens equation and image formation

    mafagafo with the save! Yeap, that gave me the correct answers of do=34.6553 cm di=417.644 cm So the distance of the lens from the screen is ≈ 418 cm and the distance of the object is 417.644 cm + 34.6553 cm ≈ 452 cm Thanks!
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    Thin lens equation and image formation

    and the question was copied and pasted from the online homework, so the question stated is typed verbatim.
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