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Carbon-14 disintegration rate in 1 mole of living carbon
this is what we worked out... (1.3x10^-12) x 12 = 1.56x10^-11 gm C14/gm C then using the equation Kb=ln2/half-life... Kb=ln2/(1.80x10^11) seconds = 3.85x10^-12 disintegrations per second Then... (3.85x10^-12) x (1.56x10^-11) = 5.97x10^-23 what have we missed?- cd95
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- Forum: Advanced Physics Homework Help
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Carbon-14 disintegration rate in 1 mole of living carbon
desperately need help with the question below. me and my dad have been working on it for hours but keep getting the answer to be 5.97x10^-23?! totally off what it should be. Q. There are about 1.3x10^-12 carbon-14 atoms for each atom of carbon-12 in living materials, and the half-life of...- cd95
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- Carbon
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- Forum: Advanced Physics Homework Help