Help with carbon dating question please

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The discussion centers on a carbon dating question regarding the calculation of disintegrations per second in carbon-14. The user and their dad calculated the number of carbon-14 atoms in a mole and the decay constant, but ended up with an incorrect result of 5.97x10^-23 disintegrations per second. They were advised to consider the total number of atoms in one mole, which is Avogadro's number, to find the correct disintegration rate. The correct approach involves multiplying the decay rate by the total number of carbon-14 atoms present in one mole. This highlights the importance of understanding both radioactive decay and the scale of atoms in calculations.
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desperately need help with the question below. me and my dad have been working on it for hours but keep getting the answer to be 5.97x10^-23?! totally off what it should be.

Q. There are about 1.3x10^-12 carbon-14 atoms for each atom of carbon-12 in living materials, and the half-life of carbon-14 is 5730 years. Show that the number of disintegrations occurring in 1 mole of carbon from a living organism is 2.3 per second.

Thanks

Charley
 
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Show what you and your dad have done so far. What do you know about radioactive decay? What is half-life?

ehild
 
this is what we worked out...

(1.3x10^-12) x 12 = 1.56x10^-11 gm C14/gm C

then using the equation Kb=ln2/half-life...

Kb=ln2/(1.80x10^11) seconds = 3.85x10^-12 disintegrations per second

Then...
(3.85x10^-12) x (1.56x10^-11) = 5.97x10^-23

what have we missed?
 
How many atoms are in one mole of a substance? Remember, it is the number of disintegrations of individual atoms that you are looking for.
 
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