Help with carbon dating question please

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desperately need help with the question below. me and my dad have been working on it for hours but keep getting the answer to be 5.97x10^-23?! totally off what it should be.

Q. There are about 1.3x10^-12 carbon-14 atoms for each atom of carbon-12 in living materials, and the half-life of carbon-14 is 5730 years. Show that the number of disintegrations occurring in 1 mole of carbon from a living organism is 2.3 per second.

Thanks

Charley
 
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Show what you and your dad have done so far. What do you know about radioactive decay? What is half-life?

ehild
 
this is what we worked out...

(1.3x10^-12) x 12 = 1.56x10^-11 gm C14/gm C

then using the equation Kb=ln2/half-life...

Kb=ln2/(1.80x10^11) seconds = 3.85x10^-12 disintegrations per second

Then...
(3.85x10^-12) x (1.56x10^-11) = 5.97x10^-23

what have we missed?
 
How many atoms are in one mole of a substance? Remember, it is the number of disintegrations of individual atoms that you are looking for.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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