Recent content by CFXMSC

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    Calculate the volumetric flow of a fluid

    For Duct Continuity: \frac{\partial v}{\partial y}=0 Momentum: \rho g_y-\frac{\partial p}{\partial y}+\mu\left(\frac{\partial^2v}{\partial x^2}+\frac{\partial^2v}{\partial y^2}\right)=0 For Circular Pipe: Continuity: \frac{\partial}{\partial r}(v_z)=0 Momentum...
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    Calculate the volumetric flow of a fluid

    How could I calculate the volumetric flow of a fluid due to the weight of a piston in a cylinder? At first moment i I thought the Hagen-Poiseuille equation, but I'm not sure. Any suggestions?
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    How can enthalpy values be calculated for an isothermal process involving steam?

    I think this equation might solve your problem. \frac{dE}{dt}=\dot{Q}-\dot{W}+\overbrace{\sum_{i}\dot{m_i}\left(h_i+\frac{v_{i}^{2}}{2}+z_i \right)}^{Inlet flow}-\overbrace{\sum_{j}\dot{m_j}\left(h_j+\frac{v_{j}^{2}}{2}+z_j \right)}^{Outlet flow}
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    Solve Momentum Behavior: Get 2.72 & 2.73 Equations

    The other i got \frac{\partial \omega}{\partial t}=\frac{\mu}{\rho}\nabla \times (\nabla^2 V) What now?
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    Solve Momentum Behavior: Get 2.72 & 2.73 Equations

    Can i assume if div(V)=0 then it's a steady flow problem?
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    Solve Momentum Behavior: Get 2.72 & 2.73 Equations

    \nabla p=\rho g + \mu \nabla^2 V-\rho\frac{\partial V}{\partial t} \nabla^2 p=\nabla .(\rho g) + \mu\nabla . (\nabla^2 V)-\rho\nabla . \left(\frac{\partial V}{\partial t}\right) \nabla^2 p=\nabla .(\rho g) + \mu\nabla^2(\nabla V)-\rho\nabla . \left(\frac{\partial V}{\partial t}\right)...
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    Solve Momentum Behavior: Get 2.72 & 2.73 Equations

    I really confused... There are a lot of terms in dV/dT and gravity that become 0, but in vicosity how could i do?
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    Solve Momentum Behavior: Get 2.72 & 2.73 Equations

    i tried but it not looks simple to do
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    Solve Momentum Behavior: Get 2.72 & 2.73 Equations

    Can somobody help me how to get the 2.72 and 2.73 equation?? http://imageshack.com/a/img89/5594/kiw6.jpg
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    Question - Thermodynamics/Heat Transfer

    Show them your results! They can't argue with facts! Or they have been a bunch of ... with you
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    Question - Thermodynamics/Heat Transfer

    Easy solution. Buy a Thermo-Hygrometer and measure your room!
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    Question - Thermodynamics/Heat Transfer

    This is not a general solution. Only works because the air outside is cooler.
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    Question - Thermodynamics/Heat Transfer

    You're right! Because you're softening the heat with airflow!
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    Question - Thermodynamics/Heat Transfer

    When you have a heat source like your body, computer, sun, etc you have to have airflow to romeve it. The complete equalization of a system occurs when you don't have any heat source. Look at the equation what happen when w=0 ?
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    Question - Thermodynamics/Heat Transfer

    Without airflow it's impossible to expect your room be cooler because the convection has a higher efficiency to remove heat than conduction. It's impossible to doesn't have airflow due to the buoyancy force and other factors. Keeping your window open will help this situation but it's very hard...