Recent content by chatterbug219

Okay... -1/8(s2+4) - 1/32(s+2) + 1/32(s-2) So do I multiply 2s2+as+b by -1/8(s2+4) - 1/32(s+2) + 1/32(s-2)? Is that you were saying? But how do I take the inverse Laplace of 2s2+as+b? That's where I'm really confused

So I got the partial fractions for the first one, but not the second one becaue the a and b are throwing me off...I don't know what to do with them in order to get the partial fractions of [2s2+as+b]/[(s-2)(s+2)(s2+4)]

I've been trying to do the partial fractions for both...so far all I have is 1/(s2+1)(s4-16) where I get [As+B/(s2+1)] + [(Cs+D)/(s4-16)] which simplifies to [As(s4-16)]+[B(s4-16)]+[Cs(s2+1)]+[D(s2+1)] and D=1 & C=-2/5...but I can't seem to get A or B to cancel so I can solve for them...

F(s)G(s)

So I did that and I got Y= 30[1/(s2+1)(s4-16)] + (2s2+as+b)/(s4-16) Do I do partial fractions for this now to get a and b? Then take the inverse Laplace?

Okay, understandable...but how do I start the problem? I'm still confused about how to start...

(x2-4)(x2+4)=0 x=2 But how do I use that to solve the differential?

No...if you plug in the initial conditions they final answers don't match up... Only 2 works

Homework Statement Solve the differential equation y(iv)(t) - 16y(t) = 30sint subject to y(0) = 0, y'(0) = 2, y"(∏) = 0, y'"(∏) = -18 Homework Equations There is a Laplace transform table attached if needed :) The Attempt at a Solution I tried making it homogeneous and then...

Well if it is convolution then it would just be F(s)*G(s) But I was more concerned about whether or not it actually was convolution. Because its y' and y, and those are both completely different, then it would be convolution then? So I would need to take the Integral of y'(u) and y(t-u)...

So B = 1/2 And plugging that in... an = (1/2)(4n) for the particular solution Making the general solution: an = A(2)n + (1/2)(4n) Right?

Oh my gosh yes there was supposed to be a z' in the first equation So it is: y'(t) + z'(t) = t The second equation is correct though, so sorry for any confusion!

Homework Statement Solve the system of differential equations: y'(t) + z(t) = t y"(t) - z(t) = e-t Subject to y(0) = 3, y'(0) = -2, and z(0) = 0 Homework Equations My professor did an example in class that was much simpler and solved it using Kramer's rule. The Attempt at a...

Homework Statement Solve the difference equation: an+2 - 5an+1 + 6an = 4n Subject to a0 = 0 & a1 = 1 Homework Equations an = Arn The Attempt at a Solution I got two solutions for the first part for when it is homogeneous by substituting an = Arn into the equation and solving for...

Homework Statement \int y'(u)y(t-u)du = 24t3 The integral goes from t (top) to 0 (bottom) With y(0) = 0 Homework Equations I want to say it kind of looks like a convolution problem \int f(u)g(t-u)du The integral goes from t (top) to 0 (bottom) The Attempt at a Solution I have no idea...