Recent content by ChemRookie
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Can Organic Chem Improve Existing Products for Health and Environment Solutions?
anybody have any ? I cannot find anything.- ChemRookie
- Post #2
- Forum: Chemistry
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Can Organic Chem Improve Existing Products for Health and Environment Solutions?
Hey, I have a question which asks me to provide two examples of how organic chem can be used to improve existing products and therefore provide solutions to newly identified health or environment problems. One example is unleaded gasoline, instead of leaded. What are some others? I've...- ChemRookie
- Thread
- Chem Organic Organic chem
- Replies: 3
- Forum: Chemistry
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What is the dissociation constant for hydroflouric acid?
thanks for your effort. I get it more, but I am still not comfortable with this. I'm going to need to give it a look more later, and keep looking back at it more and more.- ChemRookie
- Post #6
- Forum: Introductory Physics Homework Help
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What is the dissociation constant for hydroflouric acid?
oh boy, I have hated this equilibrium unit. I don't follow exactly. can you define some of the things? and is molarity (moles)? that be 0.1.- ChemRookie
- Post #3
- Forum: Introductory Physics Homework Help
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What is the dissociation constant for hydroflouric acid?
I understand this tells us how strongly binded a solution is. So I hve hydroflouric acid, it says it contains 2.0g of HF per litre and has a PH of 2.2. How do I figure what the dissociation constant for HF is? Thanks- ChemRookie
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- Constant Dissociation
- Replies: 6
- Forum: Introductory Physics Homework Help
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Formation of products is strongly favoured in the acid-base system
yes it is. Sorry, didn't know how to put it in properly.- ChemRookie
- Post #3
- Forum: Introductory Physics Homework Help
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Formation of products is strongly favoured in the acid-base system
The formation of products is strongly favoured in the acid-base system: HX + B- <--- HB + X- ----> a) Identify the bases competing for protons. b) Which base is stronger? c) Which is the weaker acid, HX or HB? d) Does the K for this system have a large or small value...- ChemRookie
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- Formation System
- Replies: 3
- Forum: Introductory Physics Homework Help
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Convert Litres to Moles: Step-by-Step Guide
how come? explain..what formula do I use then?- ChemRookie
- Post #17
- Forum: Introductory Physics Homework Help
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Convert Litres to Moles: Step-by-Step Guide
thanks..now I get it.- ChemRookie
- Post #12
- Forum: Introductory Physics Homework Help
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How Do You Calculate Activation Energy and Heat of Reaction?
For the reaction CO + NO2 ----> CO2 + NO the activation energy for the forward reaction is 135kj/mol of CO reacted. a) determine the heat of reaction b) from the data given, and the deltaHr for the reaction, determine the activation energy for the reverse reaction c) draw and label a...- ChemRookie
- Thread
- Heat Reaction
- Replies: 2
- Forum: Introductory Physics Homework Help
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Convert Litres to Moles: Step-by-Step Guide
huh? I don't get it.- ChemRookie
- Post #9
- Forum: Introductory Physics Homework Help
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Convert Litres to Moles: Step-by-Step Guide
the info I have is: a 1L container with 5mL of water helt at 20degcel I need to find the vapour pressure. I'm supposed to use PV=nrt right? how do I get n though?- ChemRookie
- Post #7
- Forum: Introductory Physics Homework Help
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Mutiple Choice - Equilibrium state
1. Consider a stoppered flask containing benzene, iodine, and air, which has reached equilibrium at 298K. Which one of the following statements converning the system at equilibrium is true? a) The pressure of the vapour phase is not constant b) Evaporation of the liquid continues. c) The...- ChemRookie
- Thread
- Choice Equilibrium State
- Replies: 1
- Forum: Introductory Physics Homework Help
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Convert Litres to Moles: Step-by-Step Guide
How would you go about changing liters, like 1L into moles? Thanks- ChemRookie
- Thread
- Moles
- Replies: 17
- Forum: Introductory Physics Homework Help
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Equilibrium Constant of A(g) 2B(g)+C(g) at Temperature t
can u explain to me how u set that up? and how do you solve it? (do the calculations)- ChemRookie
- Post #4
- Forum: Chemistry