Recent content by Chipset3600

Hi, I'm having problems to solve this equation, pls help me: $$\left( 2+\sqrt {2}\right) ^{x}+\left( 2-\sqrt {2}\right) ^{x}=4$$

Actually the problem isn't solve the integral, as you can see in my link " " with my solution i found a particular solution that isn't the same of book: "y = 1".

$$\[y'sin(x)= yln(y)\] $$ Hi, I am trying to solve this one but i can't find the same result of the book: Here is my solution:

is to find the solution transforming to polar coordinates.

Hello, can you guys help me please with this differential equation from Demidovitch book, is to find the solution transforming to polar coordinates :

Other way to solve it:

is a rule of sequences that I found. If i use this rule in this exercise: And apply limit in booth sides i will have the same result. But i want to know why this property is true...

There is no sequence, is just to prove...

I found this on the internet, but did not find the proof. Curious to me is that the the ratio and root test have the same conditions. How can i basically prove this equality? $$\frac{a_{n+1}}{a_{n}} = \sqrt[n]{a_{n}}$$ Thank you!

The definition used is that it was strange for me... My teacher give me other solution. Taking the limit it will be equal to 1. $$a_{n} = (\frac{1}{3})^{\frac{1}{n!}}$$

Im really trying to understand, but sorry! resolution is too advanced for me to realize

Still don't understanding, and i never study "difference equation".

I don't understood... Why u said that : $$\lambda_{n} = \ln a_{n}$$ ?

converge or diverge? $$\sum_{n=1}^{^{\infty }}a_{n} $$ $$a_{1}= \frac{1}{3}, a_{n+1}= \sqrt[n]{a_{n}} $$ Im having problems to solve this exercise, i would like to see your solutions

thank you, I would not get the response so soon!