Recent content by chompysj

Homework Statement Homework Equations a^2 + b^2 = c^2 A= (1/2)bh The Attempt at a Solution 1)I labeled the distance traveled on the ocean as y and the distance traveled on land as x. 2)This one's kinda hard to describe: you know how the 100 yd distance and the shoreline form...

Oh right! The 100^2 turned to 0 because it is an integer and you can't differentiate it anymore. The x disappeared because it is only to the one-power.

I got the ( 2 * -1) part from differentiating (50-x)^2.

Umm, all I can tell is that you must have gotten the derivative out of (1/2) x (y') x (y^(-1/2)) But I don't really understand how you got that. See, I'm not very good at using the Chain Rule, and what I did was just \frac{1}{2} x \sqrt{0 + (50-2)^{2}}^{-\frac{1}{2}} x (2 x (-1))

Would the derivative be -(50-x)^{2} But how would taking the derivative help me? Is it related to the 40 lb/ft and the 30 lb/ft?

So y would be: \sqrt{100^2 + (50-x)^2} Now do I take the derivative of that?

Thanks for all your help!

Homework Statement You're building a walkway from the corner of one building to the corner of another building. The diagram looks like this. The street is 100 ft wide, and 50 ft long. The walkway will weigh 40 pounds per feet when it is parallel to the street and 30 pounds per feet when it is...

I'm supposed to find the rate at which the volume of a cone is changing, when r and h are a certain amount (the r and h are both changing at a constant rate). So except for pi there are no constants.

Hi, I'm working on a related rates problem, and I need to find the derivative of the volume of a cone. So the equation is: V = (1/3) (pi) (r^2) (h) I'm not sure how to find the derivative. Would the whole thing turn out to be 0? Or do I need to use the product rule? Please help...

That's it? I finally got it right??! YESSSS! [SIZE="4"]Thank you so much! You have been so incredibly patient and nice and wonderful to a hopeless case like me! Thank you! Thank you!

So it should be the other way around? As in: T2 - T1 = m2 (a)

T1 - T2 = m2 (a)

T1 and T2, then?

T2 and T3 are acting on m2? Thanks for correcting my mistake about the net force. I think I wanted to write 'applied force' instead but somehow screwed up.