Recent content by chrisy2012

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    Line Integral of a parametric curve

    The entire question is posted correctly.
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    Line Integral of a parametric curve

    But I am suppose to integrate over the arclength(ds). I'm suppose to parametrize the curve with respect to t so that the curve imoves along 1 unit of length per unit of time. That's how I got the bounds for the integral
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    Line Integral of a parametric curve

    Homework Statement Evaluate the line integral over the curve C \int_{C}^{}e^xdx where C is the arc of the curve x=y^3 from (-1,-1) to (1,1) Homework Equations \int_{C}^{}f(x,y)ds=\int_{a}^{b}f(x(t),y(t))\sqrt((\frac{dx}{dt})^2+(\frac{dy}{dt})^2)dt The Attempt at a Solution I tried...
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    Engineering Electrical circuit general question

    Oh I got it, the professor explained that the 3 ohm resistor is on the side of a short, so the current would not reach there. Therefore it's 0.
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    Engineering Electrical circuit general question

    oops i swear i had it when i posted it. anyways it should be there now
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    Engineering Electrical circuit general question

    Homework Statement see thumbnail second part Homework Equations V=IR The Attempt at a Solution I remember the professor saying that current throughout a circuit is constant no matter where it is. So adding all of the resistance together it should be 12/10 or 6/5 Ampere's. Is this...
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    Simple Harmonic Motion on a moving platform

    I had my physics midterm today and I totally blanked out. I want to know how to solve it for next time. So In the picture, there are two springs connected to the mass on a platform. a) if the platform is at rest, find the angular frequency the expression for angular frequency is...
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    Double integral over the area of a square

    Thanks for the reply guys, I asked the TA today and she says you have to divide it up into two identical triangles. so the answer would be ∫ 0 to ∏/4 of ( ∫ 0 to secθ (rdr))dθ which would equal to 1/2. But since there are two of the triangles the area would equate to 1. So it all works out :)
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    Double integral over the area of a square

    Homework Statement Find the area of a square with each side measuring 1 using double integral and change of euclidean coordinates to polar coordinate. Homework Equations x=rcosθ y=rsin0 dA=dxdy=rdrdθ The Attempt at a Solution int(int(rdr)dθ)
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    Find the domain of continuity of this function

    sorry my mistake, What i meant to say is that the domain is the xy plane except for at point (0,0). But still, how is that different from "domain of continuity"?
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    Find the domain of continuity of this function

    Homework Statement x*sin(sqrt(x^2+y^2))/sqrt(x^2+y^2) find the domain of continuity Homework Equations none The Attempt at a Solution I found the domain, which is x^2+y^2 > 0 and since x^2 >= 0 and y^2 >= 0 therefore the domain is (-inf,0) (0,inf) but the professor then asked...
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    Not your normal Trigonometry Question

    oh got it, haha thanks, it was easier than i thought
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    Not your normal Trigonometry Question

    you have to multiply by "Z" and use quadratic formula?
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    Not your normal Trigonometry Question

    I already tried that, it did not work, you have to know the value of cos(x) in order to solve it that way
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    Not your normal Trigonometry Question

    And Don't worry, it's not a take home test, it's one of the problems from mastering physics, I have already gotten the right answer but I want to know how to solve these kind of questions in case it comes up on the test.
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