Find the domain of continuity of this function

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Homework Help Overview

The problem involves determining the domain of continuity for the function \( \frac{x \sin(\sqrt{x^2+y^2})}{\sqrt{x^2+y^2}} \). Participants are exploring the differences between the domain of the function and its domain of continuity.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the initial identification of the domain as \( x^2 + y^2 > 0 \) and the confusion surrounding the distinction between this domain and the domain of continuity. There is an exploration of the function's behavior at the origin and its continuity across the plane.

Discussion Status

The discussion is ongoing, with participants questioning the definitions and implications of the terms used. Some guidance has been offered regarding the nature of the function's continuity, but no consensus has been reached on the distinction between the domain and the domain of continuity.

Contextual Notes

Participants note that the function is defined in a two-dimensional space and that the point (0,0) is a critical area of discussion regarding continuity.

chrisy2012
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Homework Statement



x*sin(sqrt(x^2+y^2))/sqrt(x^2+y^2)
find the domain of continuity

Homework Equations



none

The Attempt at a Solution



I found the domain, which is x^2+y^2 > 0 and since x^2 >= 0 and y^2 >= 0 therefore the domain is (-inf,0) (0,inf)
but the professor then asked for the "domain of continuity" and asked us to "carefully explain", i don't know how that is different from the domain i found.
 
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chrisy2012 said:

Homework Statement



x*sin(sqrt(x^2+y^2))/sqrt(x^2+y^2)
find the domain of continuity

Homework Equations



none

The Attempt at a Solution



I found the domain, which is x^2+y^2 > 0 and since x^2 >= 0 and y^2 >= 0 therefore the domain is (-inf,0) (0,inf)
That's not the domain. As you have it, the domain is all of the real line except 0. Your function has a domain that is two-dimensional; i.e., the domain is actually some subset of R2.
chrisy2012 said:
but the professor then asked for the "domain of continuity" and asked us to "carefully explain", i don't know how that is different from the domain i found.
 
Mark44 said:
That's not the domain. As you have it, the domain is all of the real line except 0. Your function has a domain that is two-dimensional; i.e., the domain is actually some subset of R2.

sorry my mistake, What i meant to say is that the domain is the xy plane except for at point (0,0). But still, how is that different from "domain of continuity"?
 
I'm not familiar with that term. Your function is defined at and continuous at every point in the plane, except (0, 0). I'm guessing that, in this case, the domain of continuity is the same as the domain.
 

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