I think this is just tricky. They will cancel out at "one point" leaving no pulses to be seen on the rope, however they will pass through each other, and continue to be pulses.
Homework Statement
I need to find a transfer function using the given functions which i have no problem with. But i don't know how to exactly define the Region Of Convergence of the resulting transfer function.
I have h1[n] and h2[n] as to be convoluted to find the transfer function. Homework...
If there is an alternating magnetic field, so there "must" be an alternating electric field, both forming the electromagnetic waves, according to Maxwell. (?) Correct me if i am wrong.
Nope you don't have to, if the number doesn't have any factors, then it is prime. This method itself checking whether the number is prime or not. You just return the number if it doesn't find any factors up to sqrt(x).
But i think you should consider the "trickyness" of the sqrt(x) as Borek...
I haven't seen someone got a real high current shock and thrown away in my life but i'll guess that'd probably be caused by the person's uncontrolled muscle spasms caused by the shock. It's just a guess.
What if a prime number close to 100 is entered? It does a calculation for all of the numbers up to that number to figure out that there is no factors of it besides itself.
Well yeah, since x/2 won't be a "prime factor" why should i consider it since i am not looking at all the divisors of x in range(1,x+1) (silly me :) ) So the range should be up to sqrt(n) right?
Hmm, i got your point. Well, you are right. If it doesn't find any factor until it reaches x/2 he won't find any other after so the program returns the x value itself. That can make it more efficient right? Correct me if i am wrong, it was a straightforward thought.
It has to do with the definition of the range function in python
for example range(1,10) means a vector of numbers
1,2,3,4,5,6,7,8,9
I agree that the definition is confusing =)
I assume rect is short for "rectangle". The question asks you either to prove duality property of continuous Fourier transform or to use it. Search for the duality, you'll see what i mean.