Thanks very much!
I think the key point is T' is not a well defined map.
As defined, for any equivalent class [a]=[c]={a, c, ...}, T'([a]) = T(a), T'([c]) = T(c), However, a-c is not guaranteed to be in Ker T (it is in U, but U is not Ker T). As a result, T'([a]) - T'([c]) = T(a-c) may not be...