thanks for the prompt reply, however i don't understand what you mean stated to the horizontal can you please elaborate for a slow poke like me.
to me it looks like B is hanging from the vertical.
Homework Statement
see here for a situation of the problem http://i40.tinypic.com/6fbblk.jpg
Homework Equations
F=ma
The Attempt at a Solution
Ok well I've solved this problem but one thing about the solution process troubles me.
Namely when trying to find the force in the bar...
Well what you're trying to do is find the total distance to the second train station... so you're told the train travels at this acceleration you've found for another 135s, you need to find the change in distance with this acceleration.
Yes that is correct however you know that u=0 right? because as you said earlier the train starts from rest, and u represents the initial velocity of the train.
2pi to 5 decimal points is 6.283185.
and the period is 6.283185, so the period is 2pi!
I'm looking at the problem statement and cannot see why the max allowable range wouldn't be 0-90, given that we are looking for the max change in distance x.
the restriction on the possible angle would i assume range from 0-90, or 0 - pi/2?
I don't get what you're saying when you say divide by 2n.
I divide theta ≈ 0.74559 + 6.28319n by 2n? I don't see how that would help me see where the angle lies.
Homework Statement
Ok well I had a real nasty equation in which i could not solve.
I used wolfram alpha to get out this answer "theta ≈ 0.74559 + 6.28319n for integer n".
can someone please tell me what this statement means.
do i assume theta in degrees equals 0.74559(180/pi)...