Recent content by Clever_name

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    Problem involving Newton's second law

    Ah i see now - its stated in the problem that it is to the horizontal! thanks for that.
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    Problem involving Newton's second law

    thanks for the prompt reply, however i don't understand what you mean stated to the horizontal can you please elaborate for a slow poke like me. to me it looks like B is hanging from the vertical.
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    Problem involving Newton's second law

    Homework Statement see here for a situation of the problem http://i40.tinypic.com/6fbblk.jpg Homework Equations F=ma The Attempt at a Solution Ok well I've solved this problem but one thing about the solution process troubles me. Namely when trying to find the force in the bar...
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    Help Laws of Motion and question help

    Well what you're trying to do is find the total distance to the second train station.... so you're told the train travels at this acceleration you've found for another 135s, you need to find the change in distance with this acceleration.
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    Help Laws of Motion and question help

    Yes that is correct however you know that u=0 right? because as you said earlier the train starts from rest, and u represents the initial velocity of the train.
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    Help Laws of Motion and question help

    as i said before use this equation..... s= ut + 1/2at^2 you know what s, u, and t are can you not solve the equation for a?
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    Help Laws of Motion and question help

    use the equation you stated, s= ut + 1/2at^2
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    Help Laws of Motion and question help

    well the question states that the train travels 225m in 30s - try using these.
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    Help Laws of Motion and question help

    Can you find the acceleration over the 225m distance given you have time?
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    Work-kinetic energy theorem

    2pi to 5 decimal points is 6.283185. and the period is 6.283185, so the period is 2pi! I'm looking at the problem statement and cannot see why the max allowable range wouldn't be 0-90, given that we are looking for the max change in distance x.
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    Work-kinetic energy theorem

    the restriction on the possible angle would i assume range from 0-90, or 0 - pi/2? I don't get what you're saying when you say divide by 2n. I divide theta ≈ 0.74559 + 6.28319n by 2n? I don't see how that would help me see where the angle lies.
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    Confused about answer wolfram alpha spat out to me.

    Ok thanks for clearing that up guys.
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    Confused about answer wolfram alpha spat out to me.

    So if i was solving an equation say something like x'(theta) =0 would n be zero when solving for theta?
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    Confused about answer wolfram alpha spat out to me.

    Homework Statement Ok well I had a real nasty equation in which i could not solve. I used wolfram alpha to get out this answer "theta ≈ 0.74559 + 6.28319n for integer n". can someone please tell me what this statement means. do i assume theta in degrees equals 0.74559(180/pi)...
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