the question is ∫dx/ x^2*√(x^2-1)
I use x=a sec ∅ x^2*√(x^2-1)= sec^2∅tan∅ x=sec ∅
dx= sec∅tan∅d∅
so it will become something like this ∫sec∅tan∅d∅/sec^2∅tan∅= ∫1/sec∅d∅=∫cos∅d∅
=sin∅+c
But how can i change this sin in...
the question is ∫ √(y^2-25)/y^3 dy..
I did found the answer which is 1/5 sec^-1(y/5)-sin2∅/20-∅/10
But mine tutorial answer is 1/5 sec^-1(y/5)- √(y^2-25)/2y^2+c
i don't know how to convert the behind part sin2∅/20-∅/10 into √(y^2-25)/2y^2