Recent content by cloudboy

That's strange. I thought xbar = My/M ? Maybe I am getting my limits messed up, I evaluated My from 0->3, because from 3->4 is symmetric.

Ok I did it again making sure to get the powers correct and I got M = 44k/5. I calculated My to be 9k/2. When I divided My/M to get xbar I got 88/45 which can't be right!

ok I watched a couple videos on youtube and this is what I came up with: M= \int_{x=-1}^2 \int_{y= 2-x}^{4- x^2} ky dydx ⇔ k\int_{y=2-x}^{4- x^2} ydy = k (y2/2) = k [(4-x^2)/2 - (2-x)/2] = k/2 [4-x^2 - 2+x] = k/2 [-x^2+x-2] then M= \int_{x=-1}^2 (k/2 [-x^2+x-2]) dx = (k/2)[(-x^3)/3 +...

Ok I'm in my first calculus class and some of unfortunately I don't even recognize some of your notation. But I do understand somewhat and will try to use this. Thanks very much. ok i am trying to figure this out. but my density function is ky, where k is some constant. it doesn't have an x value

It very well may, I just haven't learned anything about that yet. EDIT -- I am looking up double integrals, how would you apply it here?

Homework Statement Set up integrals to find M, Mx, and My for the thin plate if d(x)=ky bounded by y=2-x and y = 4-x^2 or x = sqrt(4-y) Homework Equations M = \int dm = \intd(x)dA Mx = \intydm My = \intxdm The Attempt at a Solution I broke this down into three equations. x1 =...

Thanks a lot! I got (8(x+1)(x-1)) / (3x^(1/3)) which is the right answer.

Homework Statement Trying to find all Max and Min. F(x) = x^(2/3)(x^2 - 4) Homework Equations I know to use the product rule The Attempt at a Solution I tried and got this answer: x^(10/3) + (2(x+2)(x-2)) / 3x^(1/3)

Ok I'm trying to figure out the time and I don't really know what to do

torque = moment of inertia * angular acceleration so, since net force = 1n, torque = r * F, so torque = .1N*m. Angular acceleration = t / I = .667 ms/^2 is that right?

I'm sorry, here is a picture So F_2 = 1N and F_1 = 2N and r = .10m

Homework Statement Two forces are applied to a pulley with a moment of inertia I = .15kg*m^2. The pulley is mounted so that its frictionless axle is fixed in place. 1) What is the angular acceleration of the pulley? 2) If the pulley starts from rest, how long does it take to undergo...

Ok thanks a lot! I really appreciate the help. I just didn't have a firm grasp on the concept.

ω is constant, but it is uniformly changing direction. So there has to be an angular acceleration. edit -- but since angular acceleration = tangential accel. / r -- would angular acceleration = 0?

Constant speed