Angular acceleration and force with constant angular velocity?

AI Thread Summary
A mass constrained by a string moves in a circle at a constant speed, with the tension in the string calculated at 5N. The tangential speed is determined to be sqrt(1.25) m/s, and the angular velocity is derived from this speed. The discussion clarifies that although the mass maintains a constant speed, angular acceleration is zero because the angular velocity does not change. However, there is linear acceleration due to the constant change in direction of the velocity vector, which is centripetal acceleration. Understanding these concepts helps clarify the relationship between linear and angular motion in circular dynamics.
cloudboy
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Homework Statement



A mass M=2kg moves at a constant speed constrained by a string to move in a circle with radius .5m on a frictionless table. The tension in the string is 5N.

What is the tangential speed?
What is the angular velocity?
What is the angular acceleration?
How much work has the rope done when the mass has gone through angle \pi?

Homework Equations



a_c = v^2/r
\omega=v_t/r

The Attempt at a Solution



I calculated that the tangential speed is equal to sqrt(1.25)m/s.
I also calculated that the angular velocity is (.5)(sqrt(1.25) m/s counterclockwise from the positive x-axis.

But how do I do the angular acceleration?

Is the force equal to zero, because the force is to the center and the direction is tangential?
 
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cloudboy said:
But how do I do the angular acceleration?

Is the force equal to zero, because the force is to the center and the direction is tangential?

Is the mass speeding up or slowing down, or does it have a constant speed?
 
Constant speed
 
cloudboy said:
Constant speed

So if the speed is constant, what does that say about the angular acceleration? Is the rotation rate changing?
 
ω is constant, but it is uniformly changing direction. So there has to be an angular acceleration.

edit --

but since angular acceleration = tangential accel. / r -- would angular acceleration = 0?
 
cloudboy said:
ω is constant, but it is uniformly changing direction. So there has to be an angular acceleration.

ω is not changing direction. It's a vector that's perpendicular to the plane of motion, i.e., it lies along the rotational axis. Angular acceleration, \alpha is the rate of change of ω, and if ω is constant, \alpha is zero.

On the other hand, since the linear velocity vector is changing with time, there IS linear acceleration. This acceleration is in fact the centripetal acceleration (always pointing towards the center of motion).
 
Ok thanks a lot! I really appreciate the help. I just didn't have a firm grasp on the concept.
 
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