Find derivative where f(x) has three products

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SUMMARY

The discussion focuses on finding the maximum and minimum values of the function F(x) = x^(2/3)(x^2 - 4) using the product rule for differentiation. The correct derivative is derived as (8(x+1)(x-1)) / (3x^(1/3)), confirming the application of the product rule and simplification techniques. Participants emphasize the importance of checking the domain to ensure the expression exists at critical points. The final derivative is expressed as x^(-1/3)(8/3x^2 - 8/3).

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Homework Statement



Trying to find all Max and Min.

F(x) = x^(2/3)(x^2 - 4)

Homework Equations


I know to use the product rule

The Attempt at a Solution



I tried and got this answer:

x^(10/3) + (2(x+2)(x-2)) / 3x^(1/3)
 
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You could also just multiple the x^2/3 through so that you don't have to bother with the product rule.
 
Thanks a lot! I got (8(x+1)(x-1)) / (3x^(1/3)) which is the right answer.
 
Using the product rule gives
\frac{2}{3}x^{-1/3}*(x^{2}-4) + 2*x^{5/3}

modifying this gives (try it):
x^{-1/3}*(\frac{8}{3}x^{2} - \frac{8}{3})

For min/max equal both factors of this equation to 0 and off course check the domain. Does the expression exist at min/max?
 

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