I forgot to put a negative sign in front of distance since it was to the left. -.58 m is correct. Thanks so much for sticking through this with me and helping me out cupid!
Then from (.301+X)/X = SQROOT[(Q3Q2)/(Q3Q1)]
We divide the left side of the equation to get:
.301/X+1=SQROOT[(Q3Q2)/(Q3Q1)]
Move the 1:
.301/X=SQROOT[(Q3Q2)/(Q3Q1)]-1
Move the X:
.301=[SQROOT[(Q3Q2)/(Q3Q1)]-1]X
Get X alone:
(.301)/[SQROOT[(Q3Q2)/(Q3Q1)]-1]=X
And that's the...
So K(Q3Q1)/ X2 + K(Q3Q2) /(.301+X)2 is the same as:
K(Q3Q1)/ X2 = K(Q3Q2) /(.301+X)2 (If we use the absolute value for the charges)
And Then we can turn this into
(.301+X)2 / (X)2 = [K(Q3Q2)]/[K(Q3Q1)]
Then the Ks cancel on the right side leaving you with
(.301+X)2 / (X)2 =...
Wait I guess it could look like this Q1(1.39uC)-----.301m-----Q2(-3.22 uC)-----Q3(3.33)
X being the distance from 1 to 3.
Actually does this make sense? I think Q3 on the left is actually the right setup cause in this one wouldn't it be impossible for the forces to equilibrate no matter how...
Damn. Still didn't work. So if we assume the setup is like this
Q3(3.33 uC)------X----Q1(1.39uC)-----.301m-----Q2(-3.22 uC)
The equation would turn into this correct:
K(Q3Q1)/ X2 + K(Q3Q2) /(.301+X)2 = 0
Or more plainly K(Q3Q1)/ X2 =...
OMG good call. I kept thinking it had to either be Q1------Q2----Q3 or Q1---Q3---Q2 and I kept thinking that just doesn't make sense logically cause of the charges but Q3------Q1----Q2 does make sense! Alright altering my equation to take the new positioning into account. Will tell you the result.
How do I use the force of Q1 on Q2 after I find it? I thought since one and two are stationary that force did not matter. Sorry I'm kind of slow at understanding this stuff.
Homework Statement
Three charges, Q1, Q2, and Q3 are located in a straight line. The position of Q2 is 0.301 m to the right of Q1.
Q1= 1.39x10-6 C and Q2= -3.22 x10-6 C are fixed at their positions, distance 0.301 m apart, and the charge Q3= 3.33 x10-6 C is moved along the straight line. For...