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## Homework Statement

Three charges, Q1, Q2, and Q3 are located in a straight line. The position of Q2 is 0.301 m to the right of Q1.

Q1= 1.39x10-6 C and Q2= -3.22 x10-6 C are fixed at their positions, distance 0.301 m apart, and the charge Q3= 3.33 x10-6 C is moved along the straight line. For what position of Q3 relative to Q1 is the net force on Q3 due to Q1 and Q2 zero? Use the plus sign for Q3 to the right of Q1.

## Homework Equations

F=(K(Q1Q2))/r^2

## The Attempt at a Solution

So I attempted to solve it by using X as the distance from Q1 to Q3 and built this equation:

[k(Q1Q3)]/(X^2)+[k(Q2Q3)]/[(x-.301)^2)=0

Since .301 is the distance from 1 to 2 which is fixed I assumed X-.301 was the correct way to calculate distance from 2 to 3 for that portion of the equation.

When I go throught this I get to the point where I'm at [.0417/(x^2)]= [-.0965/(x-.301)^2].

I then plug this into my graphing calculator (one side as one function, the other as another function) and then excute the intercept function to easily find X, but there is no intercept meaning that my equation above for X is wrong.

Any help is appreciated. Thank you in advance.

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