Recent content by cneedshelp

Im not sure which formula to use...

d = vt + (1/2)at^2 is that the formula?

You have to find acceleration, the formula is vf-vi over tf-ti right?

Oh haha thank you. :) Now how do you find the different times?

What is s?

An Olympic sprinter can accelerate from rest out of the blocks to a top speed of about 11.5 m/s. This is accomplished in the first 15 m of a race. What is the average acceleration of the first sprinter? Given- vi- 11.5 m/s Distance-15m Vf-? t-? Which formula do I use to find these...

So now I have Distance- 30.0m a-2.00m/s^2 vi-0m/s So can i now use the d=1/2at^2 formula? But we're solving for t making the equation t, taking the square root of 2d/a right?

How long does it take a car to travel 30.0m if it accelerates at a rate of 2.00m/s^2? Given Distance- 30.0m A-2.00m/s^2 Do I need to find vi?

I asked my teacher about it, and she said the 9.8 is always negative, so how do i work out the problems?

Why wouldn't it be negative, I thought when it said dropped from rest meant it is lower than 0?

For a freely falling object dropped from rest, what is the acceleration at the following times? a.the end of the 2nd second b. the end of the 10th second c. the end of any elapsed time t Given- A= -9.80m/s^2 Vi=0m/s Do you have to find the final velocity, then acceleration?

What I did now was 20(1000)/3600 is 6m/s using sig figs and that's the answer! right?

I got .02m but I'm not sure how to convert the hr to seconds

At highway speeds, a certain car is capable of an an acceleration of about 1.7 m/s^2. At this rate, how long does it take to accelerate from 90 km/hr to 110 km/hr? (WATCH UNITS.) Given- Time=? A=1.7m/s^2 Vi=90km/hr Vf=110km/hr Vf=vi+at Solve for t! T= vf-vi/a...