Recent content by Coldie

Thanks for the links guys, they answered my question completely!

Here's something I've always wondered about but never got around to asking anyone. We know that when an object moves very close to the speed of light, outside events from the perspective of the object begin to occur faster and faster, correct? So for every foot that such an object travels, a...

Um... bump?

Hi again, Our textbook gives us equations to find the speed of objects in relation to others in the x, y, and z planes. These are: v^'_x = \frac{v_x - u}{1 - uv_x/c^2} v^'_y = \frac{v_y}{\gamma(1 - uv_x/c^2)} v^'_z = \frac{v_z}{\gamma(1 - uv_x/c^2)} My first question is why is the...

Thanks, my only problem now remains the second part. I'm having great difficulty coming up with an equation for the circle, which seems absurd. The equation for center of mass in the y-axis is in the form \frac{1}{M}\int_{a}^{b} I'm not sure what y, nor dm, are to be. Could you please help...

Ah, the center of mass does not change, but the position of the car may! I understand now. Should I say that the car would move proportionally to the amount of mass that is displaced within the system by the fired cannonballs, or is there a better response? The equation we're given in the...

Hey guys, My first question is as follows: A cannon and a supply of cannonballs are inside a sealed railroad car of length L. The cannonballs remain in the car after hitting the far wall. a) After all the cannonballs have been fired, what is the greatest distance the car can have moved from...

I'm aware that the pulley isn't relevant except in the manner that it effects the interaction of the two masses. I only mention it because the net force on the pulley is the net force on the system, right? I don't understand why the tension force would be half of the pulling force as opposed to...

Wow, thanks, it hadn't crossed my mind to look at it that way. Am I right in subtracting the weight of the masses to find the net force on the pulley? If so, then halfing the weight of both masses combined would give the tension force?

I solved a and got 6.68N, as stated in the first post... is my solution wrong? Right now I'm asking for help on part b. [edit] Sorry, you stated right in your post that you were talking about part a, I somehow overlooked that!

Yes, the pulley and rope are massless and frictionless, sorry for not mentioning that. The net force on the pulley is 110 - 3.1(9.8) = 79.62N. Thus, the net acceleration of the system will be 25.68m/s^2. However, I'm still left with the problem of how this acceleration is, well, distributed...

Hi guys, this question is driving me up the wall because I always thought pulley system questions were easy and enjoyable to do, but this one refuses to cooperate! The question: Someone exerts a force F directly up on the axle of a pulley. Two objects, m1 of mass 1.2kg and m2 of mass 1.9kg...

Thanks, I can see now that the basic formula for DeMorgan is one for which the dual is also its negative. (-pvq) is equivalent to -p^-q. I'm still not sure why or how to explain it, though. Can you give me a hint? Does it simply have to be two statements on either side of an ^ or v?

Hi, For one of the questions in my Discrete Mathematics course, I have to find what property of a formula makes its dual formula also its negative. With a dual formula, the logical operators of "^" and "v" are reversed, the former meaning "and" and the latter meaning "or". With its negative...

Thanks for trying to help, but, as I explained, the problem is that I own a Macintosh, and the Scanner component does not seem to be present in java.util. Though I understand there are far more complex ways of taking keyboard input, I just want to know how to get Scanner onto my computer so that...