Recent content by cone

If they don't already require it, I would suggest taking a statistics course. It should be required though. Also, combinatorial mathematics helps to broaden your thinking about mathematics as well. I'm not a mathematician, but both those courses seemed to help when dealing with the real world...

it might help to think of it like this: 2/3 - 1/3 = (2-1)/3 So reverse would be the same: (2-1)/3 = 2/3 - 1/3 if 3 were negative, then the negatives would evaluate: (2-1)/-3 = 2/-3 - 1/-3 = -2/3 - (-1/3) = -2/3 + 1/3

That can't be correct. Are you sure it's not work time (t) plus paid break (b) divided by total time at work (or they are supposed to be at work) (w) or something? A = (t+b)/w So if the work time (from what I can tell of your work up) is 8.5 (=t) hours, the paid break is 1.25 (=b), and the...

Also make sure you test small numbers first and work your way up. If you run out of memory with small numbers, there may be something wrong with the code. If you are working from small to huge and back down (say 200!/199! ) make sure you work it out before going large or you'll crash (or take a...

not exactly, equality allows same operations across the equal, so to demonstrate you have to show one equation equal and then change it, such as: if a = b then a*c = b*c is multiplicative equality showing that when you multiply something on one side you do it equally on the other...

(assuming integer divide that truncates the number) For 6 from base 10 to base 2: 6%2 = 0, 6/2 = 3 3%2 = 1, 3/2 = 1 1%2 = 1, 1/2 = 0 You stop at zero on the second and the list of numbers reversed is the binary: 110 Just like you did. This works for all integer bases: For 47 from base 10...

Ah, I found the flaw in thinking that I was looking for. It was literally the word "movement" that showed me it. Well, that and trying on real world problems. I really was trying to find a movement system and make it work outside of itself. Either way, I found that the only way to really make...

It won't let me edit the OP, so here is how distribution of multiplication over addition would work in this system. I hadn't really thought it fully through when I made the first post, so didn't know the outcome at that time. b(a + c) = ba + bc (a + c)b = ab + cb which means: `1 * 5 = -`1 *...

-(-5) would be an operation that changes the number line from negative to positive. (-1)(-5) would be and operation of 1*5 on the same number line. Basically, if you viewed negative numbers with a "`" it may be easier to see how it seems: `1*`5 = `5 -`5 = 5 That's how it's...

(-3)(-2)+ (-3)(2)= -6 + 6= 0 (-3)(-2)+ (-3)(-2)= -6 - 6= -12 (-3)(-2)+ (3)(-2)= -6 - 6= -12 It is more complex though, so not saying it should be taken. However, I'm not sure why commutativity is assumed true other than that it fit the definitions that were already in place I would agree that...

No, however, it is different. The negative are kind of like a different number line, but not thrown out. -3 would represents the element which satisfies 0 - 3. It would be a translation from one line to the other. For (-3)(-2) = -6 = -(3)(2) to work, it would have to be defined as such. Not...

This is similar to the question However, it is slightly different. It's probably more of a philosophy of math topic, however, I posted this on a philosophy forum and can't find many people interested in math there. I hope it hasn't been overly discussed. Thank you for reading even if you don't...

You can focus on x2 - x + 1 to see an approach you probably know (x-1)2 = x2 - x - x + 1 = x2 - 2*x + 1 So, what added to itself would equal 1 instead of 2 to make x2 - x + C and how would you get it there. If you find out how to do this, you can figure out the rest.