Recent content by connorc234
-
C
Why Does a Rolling Sphere Climb Higher Than a Sliding Particle?
Homework Statement A uniform sphere and a particle are sent one-by-one with the same initial speed up the same incline. Each rises to a maximum height before falling back towards the starting point. The sphere rolls without slipping; the particle slides without friction. Use conservation of...- connorc234
- Thread
- Inertia Moment Moment of inertia Spheres
- Replies: 2
- Forum: Introductory Physics Homework Help
-
C
Basic thermodynamics, reversible engine process
I appreciate your help, but I was able to complete the question by myself after you guys got me rolling. I'm fairly confident I got the right answers. Thanks again, Connor- connorc234
- Post #8
- Forum: Introductory Physics Homework Help
-
C
Basic thermodynamics, reversible engine process
b to c and d to a both zero work since isochoric afaik a to b W=2pV c to d W= -2pV/3- connorc234
- Post #6
- Forum: Introductory Physics Homework Help
-
C
Basic thermodynamics, reversible engine process
ok i used pv=nRT taking R to be 8.31 p and V are known at all times so I just found the temperatures for each point. a - pV/8.31 b - 3pV/8.31 c - pV/8.31 d - pV/24.93 then for the work since 2 are isochoric they are zero... the others a-b W=2pV c-d W= -2pv/3 adding them gives 4pV/3 is any...- connorc234
- Post #5
- Forum: Introductory Physics Homework Help
-
C
Basic thermodynamics, reversible engine process
Homework Statement http://i.imgur.com/jmLqca9.jpg pic of question Homework Equations W = p x dV, Q = dU + W etc The Attempt at a Solution I know what the different stages are, a-b and c-d are isobaric, d-a and b-c are isochoric and I believe the answer to a, the net work done in one cycle...- connorc234
- Thread
- Basic thermodynamics Engine Process Reversible Thermodynamics
- Replies: 8
- Forum: Introductory Physics Homework Help
-
C
Circular Motion: Solving for Velocity using Vector Cross Product
yeha i got it now thanks a lot man really appreciate it.- connorc234
- Post #19
- Forum: Introductory Physics Homework Help
-
C
Circular Motion: Solving for Velocity using Vector Cross Product
ok thanks. one last question. should i use the position vector for r (1.3sin40 i -1.3cos40 j) or its modulus?- connorc234
- Post #17
- Forum: Introductory Physics Homework Help
-
C
Circular Motion: Solving for Velocity using Vector Cross Product
http://i.imgur.com/VL6r6Oo.jpg i have this which i think might be relevant. does this mean i can just use v=wr as normal?- connorc234
- Post #15
- Forum: Introductory Physics Homework Help
-
C
Circular Motion: Solving for Velocity using Vector Cross Product
vbx problem now though... using the 2 answers for a and b with the equation v=wr in vector form, gives me 0i + 0j + 0k...? is this meant to happen?- connorc234
- Post #13
- Forum: Introductory Physics Homework Help
-
C
Circular Motion: Solving for Velocity using Vector Cross Product
that's the k or z direction right? so the vector would be 0i + 0j + 2pi/1.4 k ?- connorc234
- Post #9
- Forum: Introductory Physics Homework Help
-
C
Circular Motion: Solving for Velocity using Vector Cross Product
i've learned the right hand rule yeah, don't think I've seen the cross product before. but i don't know if they just want 2pi/1.4 or if they want me to split it into i's j's and k's somehow. and if so i have no idea how to do that. the fact that they ask for a position vector after that question...- connorc234
- Post #7
- Forum: Introductory Physics Homework Help
-
C
Circular Motion: Solving for Velocity using Vector Cross Product
2π/1.4 something i don't understand is that the question is asking for vectors, so how would i put ω = 2π/1.4 in vector form? should I use my answer for b in the future questions, since it's continuously asking for vectors?- connorc234
- Post #5
- Forum: Introductory Physics Homework Help
-
C
Circular Motion: Solving for Velocity using Vector Cross Product
sorry, changed it to a better picture. for a. T = 1/1.4 where T is the period t = (40/360)(1/1.4) to find the time taken for the mass to turn through 40 degrees =(1/12.6) w = dtheta/dt = 40/(1/12.6) w = (40)(12.6) = 504 radpersec b. used trigonometry with theta = 40 and...- connorc234
- Post #3
- Forum: Introductory Physics Homework Help
-
C
Circular Motion: Solving for Velocity using Vector Cross Product
Homework Statement http://i.imgur.com/Nbg3Nrc.jpg pic of question Homework Equations v = wr, s=rtheta t=1/f etc The Attempt at a Solution i did a, got 504 radpersec and then did b, r = 1.3sin40 i - 1.3cos40 j + 0 k but I'm not sure if I'm doing it right. can anyone help me and point me in...- connorc234
- Thread
- Circular Circular motion Motion
- Replies: 18
- Forum: Introductory Physics Homework Help