yes only before the collision are v1 and v2 are different. however the 2 balls ''stick together'' therefore the velocity is the same for both of them after the collision
[b]1. an ice cone 25mm high with a max radius of 15mm is floating apex downwards in a glass of water. if the ice cone has a mass of 5.3g to what depth will the cone be immersed? density of water is 1000kg/m^3
i know from the law of flotation that the weight of a floating body is equal to...
pax= 6v1 pay = 0
pbx= 8v2cos30 pby = 8v2sin30
pcx= 6v1 +8v2cos30 = 12.9v pcy = 8v2sin30= 4v
(12.9v^2 + 4v^2)^.5 = 13.5v
so 58 = 13.5v
v= 4.2
a is moving along the x-axis and b is moving below a but is heading towards a. the angle between them is 30
so its the kinetic formula cos it wouldn't make sense to use the hookes law right? but since when can u have the spring constant in a kinetic energy formula?
Q. Two objects A and B are moving on a frictionless horizontal surface. A has a mass of 6kg and speed of 3m/s , B has a *** of 8kg and a speed of 5m/s. if they collide and stick together the speed in m/s of the composite object after the collision is:
diagram:
A----------------------> X...
Q. An object of mass o.4kg slides at 8m/s across a frictionless path before striking one end of a spring that is fixed at the other end. the spring constant is 80N/m. the maximum distance, in metres, by which the spring compressed is : ans?
I a not sure wether to use hookes law (f=ks)...