Recent content by Coushander

Double r obviously. I had that thought while I was eating a sandwich. d = 8.08mm (correct within rounding)

Homework Statement A paint sprayer pumps air through a constriction in a 2.50-cm diameter pipe, as shown in the figure. The flow causes the pressure in the constricted area to drop and paint rises up the feed tube and enters the air stream. The speed of the air stream in the 2.50-cm diameter...

C) Total Area at 2.5m = 4(pi)(2.5m)2 = 25(pi)m2 Sub-Area = 3.25cm2 = 3.25x10-4m2 Sub area/total area = 4.14x10-6 Energy at sub-area = (total energy)(fraction) total energy = 1.015x106 W Correct Answer. B) I = P/A P = 1.015x106 W A = 4(pi)(10m)2 = 400(pi)m2 I =...

I mean I don't know the equation to find out "total energy given out each second"

But the issue is that I don't know that equation either.

It was something that came up on mastering physics only once. So I don't remember how to link 1/d12 and 1/d22

So if the 3.25cm^2 area is only part of the sphere at 2.5m, how can I go about using that to find the area at 10m? Like unless I'm supposed to just times it by four or something I don't know.

Okay but how does the 2.5m radius factor into that?

Homework Statement A tiny vibrating source sends waves uniformly in all directions. An area of 3.25 cm2 on a sphere of radius 2.50 m centered on the source receives energy at a rate of 4.20 J/s. (a) What is the intensity of the waves at 2.50 m from the source? (b) What is the intensity of...

You're right, it was an arithmetic error. Working it through again gave me 88.57dB this time (did it twice to make sure).

(25cm)(gravity)(density of Hg) + d(gravity)(water density) + h(gravity)(water density) = d(gravity)(water density) + (25cm)(gravity)(density of Hg)? Wouldn't that just cancel out? Just looking at it makes me think that I should use (25cm)(gravity)(density of water) + d(gravity)(water...

(25cm)(gravity)(density of Hg) + d(gravity)(water density) + h(gravity)(water density) = d(gravity)(water density) + h(gravity)(water density) ? or maybe (25cm)(gravity)(density of Hg) + d(gravity)(water density) + h(gravity)(water density) = d(gravity)(water density) + h(gravity)(water...

Homework Statement If the intensity level at distance d of one trombone is 70 dB, what is the intensity level of 76 identical trombones, all at distance d? Homework Equations β = (10 dB) log10(I/I0) I0= 1.0 x 10-12 W/m2 I = power/area The Attempt at a Solution 70db = 10db log10(I/I0)...

How do I generate an equation for the point in the right tube?

So (25cm)(gravity)(density of Hg) + d(gravity)(water density) + h(gravity)(water density) = pressure at water-Hg interface in the left tube = pressure at equal point in right tube?