I just got the correct answer:
I had 60 because I was thinking we needed to total amount of microprocessor
Step 1:
Binomcdf(4,0.095,0,1)
=0.9524
Step2:
Variance formula for Binomial
= npq
with n = 15 and p = 0.9524 and q = (1-0.9524)
=0.679136
Okay;
Step 1:
15*4=60
Binomcdf(60,0.095,0,1)
=0.018287
Step2:
Variance formula for Binomial
= npq
with n = 15 and p = 0.018287 and q = (1-0.018287)
= 0.269287
I did that:
Binomcdf(15,0.095,0,1)
=0.576018
Variance formula for Binomial
= npq
with n = 4 and p = 0.576018 and q = (1-0.576018)
= 0.976885
Does that make sense ?
Thank you for your help and time.
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